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3 years ago

QUICK PLZZ!!! If m<ABD = 71°, what are m<ABC and m<DBC?

Mathematics

1 answer:

suter [353]3 years ago

7 0

Answer:

m<ABC = 45

m<DBC = 34°

Step-by-step explanation:

Given:

m<ABD = 79°

m<ABC = (8x - 3)°

m<DBC = (5x + 4)°

Step 1: Generate an equation to find the value of x

m<ABC + m<DBC = m<ABD (angle addition postulate)

(8x - 3) + (5x + 4) = 79

Solve for x

8x - 3 + 5x + 4 = 79

13x + 1 = 79

Subtract 1 from both sides

13x + 1 - 1 = 79 - 1

13x = 78

Divide both sides by 13

x = 6

Step 2: find m<ABC and m<DBC by plugging the value of x into the expression of each angle

m<ABC = (8x - 3)°

m<ABC = 8(6) - 3 = 48 - 3 = 45°

m<DBC = (5x + 4)°

m<DBC = 5(6) + 4 = 30 + 4 = 34°

Step-by-step explanation:

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--------------------------------------------------

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QUICK PLZZ!!! If m<ABD = 71°, what are m<ABC and m<DBC?​

QUICK PLZZ!!! If m<ABD = 71°, what are m<ABC and m<DBC?