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lapo4ka [179]
3 years ago
8

The second hand on a clock is 8 \text{ cm}8 cm8, space, c, m long. What is the distance the tip of the second hand travels in 10

1010 minutes? Round your answer to the nearest \text{cm}cmc, m. \text{cm}cm
Mathematics
1 answer:
arsen [322]3 years ago
5 0

Answer:

The distance the tip of the second hand travels in 10 minutes is 502 cm.

Step-by-step explanation:

Given : The second hand on a clock is 8 cm long.

To find : What is the distance the tip of the second hand travels in 10 minutes?

Solution :

The circumference of clock is C=2\pi r

The radius is r=8 cm

C=2\times 8\times \pi

C=16\pi

i.e. in 1 minute it cover  16\pi

In 10 minutes it cover  16\pi\times 10

In 10 minutes it cover  160\times 3.14

In 10 minutes it cover  502.4

Therefore, the distance the tip of the second hand travels in 10 minutes is 502 cm.

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Answer:

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And solving for X we got:

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Step-by-step explanation:

For this problem we can set upt the following notation

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And we know that the total revenue  for Wednesday was 831.60. So then we can set up the following equation for the total revenue

5.10 X +9.00 Y = 831.60

We also know that for Wedneday we have two times tickets for adults compared to child so we have

Y =2x

And using this condition we have:

5.10 X + 18 X = 831.60

And solving for X we got:

X= \frac{831.60}{23.1}=36

So then the number of tickets sold for child are 36

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