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nevsk [136]
2 years ago
6

Can some one help me find x?

Mathematics
2 answers:
zhenek [66]2 years ago
6 0
Answer: x=20


...........................
Gnom [1K]2 years ago
4 0

Answer:

x = 20

Step-by-step explanation:

Exterior angles are equal.

7x - 3 = 6x + 17

Add 3 and subtract 6x to both sides.

x = 20 is the answer.

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Pick a expression that matches the written description Subtract a from the quotient of 6 and B
Luba_88 [7]

An expression that is equivalent to the statement Subtract a from the quotient of 6 and B is 6/b - a

<h3>How to write equivalent expression</h3>

Given statement

Subtract a from the quotient of 6 and B

  • The quotient of 6 and B can be written as 6/B

  • a subtracted from 6/B is written as

6/B - a

Therefore, the correct option equivalent to the statement is option A) 6/B - a

Learn more about equivalent expression:

brainly.com/question/2972832

3 0
2 years ago
Read 2 more answers
X-1/4x^2+7x+3 divided by 2x^2+4x-6/4x^2+11x+6
Zina [86]
You pretty much just flip the second fraction and factor 

8 0
3 years ago
27.38 + 384 -<br> I don’t know the answer can I please have some help
Katen [24]

Answer:

411.38

Step-by-step explanation:

When you add 27.38 and 384 together, you get 411.38.

3 0
2 years ago
Please help!! this is due TODAY!
Rzqust [24]
C I’m pretty sure that’s what is it
7 0
3 years ago
Consider two boxes, one containing one black and one white marble, the other, two black and one white marble. A box is selected
valina [46]

Answer:

\frac{7}{12}

Step-by-step explanation:

Probability refers to chance of happening of some event.

Conditional probability is the probability of an event A, given that another event B has already occurred.

B_1,B_2 denote the two boxes.

In box B_1:

No. of black balls = 1

No. of white balls = 1

In box B_2:

No. of black balls = 2

No. of white balls = 1

Let B, W denote black and white marble.

So, probability that either of the boxes B_1,B_2 is chosen is \frac{1}{2}

Probability that a black ball is chosen from box B_1 = \frac{1}{2}

Probability that a black ball is chosen from box B_2=\frac{2}{3}

To find:probability that the marble is black

Solution:

Probability that the marble is black = \frac{1}{2}(\frac{1}{2} )+\frac{1}{2}(\frac{2}{3})=\frac{1}{4}+\frac{1}{3}=\frac{7}{12}

6 0
3 years ago
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