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Hoochie [10]
3 years ago
6

Latoya has a large collection of basketball cards. She gave half to a friend and a 1/4 to her brother. She still has 75 cards le

ft. How many did she start with?
Mathematics
2 answers:
Murljashka [212]3 years ago
4 0

Answer: She had 200 cards to start with

Step-by-step explanation:

Let x = the amount of cards she had initially. This means she had x cards to start with.

She gave half of the cards she had to a friend. This means she gave her friend x/2 cards. She is left with with (x-x/2) = x/2 cards.

She also gave 1/4 of the remaining cards to her brother. This means that she gave (1/4 × x/2) = x/8 cards to her brother.

Remaining number of cards will be x/2 - x/8 = (4x-x)/8 = 3x/8

She still has 75 cards left. This means

3x/8 = 75

Cross multiplying with 8, it becomes

3x = 75×8 = 600

x = 600/3 = 200

She had 200 cards to start with.

bixtya [17]3 years ago
4 0

Latoya started with 300 cards.

<u>Solution: </u>

Given that Latoya has a large collection of basketball cards

She gave half to a friend.  

She gave \frac{1}{4} to her brother.

Number of card left = 75

Need to calculate number of cards Latoya was having at starting.  Let’s assume number of cards at starting be represented by variable x.  As she gave half to a friend,

So number of cards given to friend =\frac{1}{2} \times x=\frac{x}{2}

Number of cards given to brother =\frac{1}{4} \times x=\frac{x}{4}

Number of cards left = number of cards at starting - number of cards given to friend - Number of cards given to brother

\begin{array}{l}{\Rightarrow 75=x-\frac{x}{2}-\frac{x}{4}} \\\\ {\Rightarrow 75=x-\left(\frac{x}{2}+\frac{x}{4}\right)} \\\\ {\Rightarrow 75=x-\left(\frac{2 x+x}{4}\right)} \\\\ {\Rightarrow 75=x-\left(\frac{3 x}{4}\right)} \\\\ {\Rightarrow 75=x-3 x=\frac{x}{4}} \\\\ {\Rightarrow 75 \times 4=x} \\\\ {\Rightarrow 300=x}\end{array}

Number of cards at starting = x = 300

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<u>ANSWER</u>

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<u>EXPLANATION</u>

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Rus_ich [418]

Answer:

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Step-by-step explanation:

A triangle always consists of it being 180 degrees. The box on the triangle on angle A depicts that it is a right angle, 90 degrees. And since Angle B is given at 45, angle C must be 45 degrees as well, since 180-45-90 (triangle angles=given angles for A and B) equal up to 45. When the angles beside the right angle is both identical and the same, the sides that correspond with that triangle is also the same. AC is given at 9 feet, and since Angle C and B both have the same angles, AB must ALSO be a 9ft.

Now, since we know the two sides, it is very easy to find BC, or the hypotenuse of the triangle, using the Pythagorean Theorem: a^{2} +b^{2} =c^{2}, where a and b are sides, and c is the hypotenuse (or the long end) of a right triangle.

We can plug both 9s in for a and b since they're both the same, and it should equal to

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9^2 is 9*9, and that is 81. We have two of these so add them together to find 162. Since c^2 is equal to 162, we would need to square root both sides so we can find a number that equals c.

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We can either plug this into a calculator, and we should get something around 12.72, and that would be the same as C if you plug that value into a calculator.

You can also simplify the radical if you know how to. 162 is 81 times 2 (example) and 81 is 9*9, so we can add that to the outside and 2 is still under the radical. But this would only make sense if you know how to do that.

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Step-by-step explanation:

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