This would be a percent increase, so the formula would be:
New amount - Original amount / Original amount
Replace the numbers:
440 - 154 / 440
Simplify.
286 / 440
The chance would be 0.65, or 65%.
Answer:
Slope: 2/3
Step-by-step explanation:
You have to first write the equation into slope-intercept form...
y = mx + b
So...
-2x + 3y = -6
becomes...
3y = 2x - 6
y = 2/3x - 2
Which means...
2/3 is the slope
Hope this help :)
Let me know if there are any mistakes!!
Answer:
Z is 66. If you want an explanation, I could give it to you, FYI.
Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
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