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3 years ago

If two lines are skew lines, then they are noncoplanar. True or false

Mathematics

1 answer:

Anika [276]3 years ago

7 0

Answer:

Two lines that both lie in the same plane must either cross each other or be parallel, so skew lines can exist only in three or more dimensions. Two lines are skew if and only if they are not coplanar.

Step-by-step explanation:

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Angle LON is a straight angle Angle MON= 3x+89 Angle LOM=8x+58 Find Angle MON:

tresset_1 [31]

Answer:

Angle MON is 98°

Step-by-step explanation:

The measure of the straight angle is 180°

∵ ∠LON is a straight angle

∴ m∠LON = 180°

∵ Ray OM intersects line LN at O

∴ OM divides ∠LON into two angles ∠LOM and ∠MON

∴ m∠LOM + m∠MON = m∠LON

- Substitute m∠LON by 180°

∴ m∠LOM + m∠MON = 180°

∵ m∠LOM = 8 x + 58

∵ m∠MON = 3 x + 89

- Substitute them in the equation above

∴ (8x + 58) + (3 x + 89) = 180°

- Add the like terms in the left hand side

∴ (8 x + 3 x) + (58 + 89) = 180°

∴ 11 x + 147 = 180

- Subtract 147 from both sides

∴ 11 x = 33

- Divide both sides by 11

∴ x = 3

Substitute the value of x in the measure of angle MON to find it

∵ m∠MON = 3(3) + 89

∴ m∠MON = 9 + 89

∴ m∠MON = 98°

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Novay_Z [31]

Answer:

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Step-by-step explanation:

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astra-53 [7]

Step-by-step explanation:

vector AB(3-(-6); 5-7)

vector AB(9;-2)

AB= $\sqrt{9^{2}+(-2)^{2} }$ = $\sqrt{85}$

M is the midpoint of AB

we have B(-5;10) and M(1;7)

let A(x;y)

(x-5)/2 = 1 ⇒ x-5 = 2⇒ x = 7

(10=y)/2 = 7⇒ 10+y = 14 ⇒y= 4

so : A(7;4)

the center of the circle is the midponit of the line joining both ends of the diameter

let A(x;y) be the other end

(-2+x)/2 = 2 ⇒ -2+x = 4⇒ x= 6

(5=y) = -1 ⇒ 5+y = -2 ⇒ y= -7

so the coordinates of the other end are (6; -7)

A,B and C are collinear such as AB=BC so b is the midpoint of AC

(-5+1)/2 = y ⇒ y = -4/2 ⇒ y = -2

((-3=x)/2 = 7 ⇒ -3+x = 14 ⇒ x = 17

so x= 17 and y = -2

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2 years ago