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scoundrel [369]
3 years ago
10

Brendan and carnal each made a bowl of punch. Carnal used 9 1/6 times as Brendan did. If Brendan used 1/3 of a cup of lemonade,

how many cups of lemonade did darnay use?
Mathematics
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

Carnal used \frac{55}{18} \ cups \ \ \ OR \ \ \ 3\frac{1}{18} \ cups of lemonade.

Step-by-step explanation:

Given:

Amount of lemonade Brendan used = \frac{1}{3} \ cups

Also Given:

Carnal used 9\frac{1}{6} times as Brendan did.

We need to find the Amount of lemonade Carnal Used.

Now we know that;

Carnal used 9\frac{1}{6} times as Brendan did.

9\frac{1}{6} can be Rewritten as \frac{55}{6}

Hence Carnal used \frac{55}{6}  times as Brendan did.

It means that Amount of Lemonade Carnal used is equal  \frac{55}{6}  times Amount of lemonade Brendan used.

framing in equation form we get;

Amount of Lemonade Carnal used = \frac{55}{6}\times \frac{1}{3} = \frac{55}{18} \ cups \ \ \ OR \ \ \ 3\frac{1}{18} \ cups

Hence Carnal used \frac{55}{18} \ cups \ \ \ OR \ \ \ 3\frac{1}{18} \ cups of lemonade.

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\sigma=\sqrt{\frac{\sum (x-\overline{x})^2}{n}}

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