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scoundrel [369]
3 years ago
10

Brendan and carnal each made a bowl of punch. Carnal used 9 1/6 times as Brendan did. If Brendan used 1/3 of a cup of lemonade,

how many cups of lemonade did darnay use?
Mathematics
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

Carnal used \frac{55}{18} \ cups \ \ \ OR \ \ \ 3\frac{1}{18} \ cups of lemonade.

Step-by-step explanation:

Given:

Amount of lemonade Brendan used = \frac{1}{3} \ cups

Also Given:

Carnal used 9\frac{1}{6} times as Brendan did.

We need to find the Amount of lemonade Carnal Used.

Now we know that;

Carnal used 9\frac{1}{6} times as Brendan did.

9\frac{1}{6} can be Rewritten as \frac{55}{6}

Hence Carnal used \frac{55}{6}  times as Brendan did.

It means that Amount of Lemonade Carnal used is equal  \frac{55}{6}  times Amount of lemonade Brendan used.

framing in equation form we get;

Amount of Lemonade Carnal used = \frac{55}{6}\times \frac{1}{3} = \frac{55}{18} \ cups \ \ \ OR \ \ \ 3\frac{1}{18} \ cups

Hence Carnal used \frac{55}{18} \ cups \ \ \ OR \ \ \ 3\frac{1}{18} \ cups of lemonade.

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Answer:

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Step-by-step explanation:

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In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

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