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Natali [406]
3 years ago
5

Simplify

Mathematics
2 answers:
Zanzabum3 years ago
5 0

\left(\dfrac{h^{12}}{h^4}\right)^3\\\\\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\left(h^{12-4}\right)^3=\left(h^8\right)^3\\\\\text{use}\ (a^n)^m=a^{n\cdot m}\\\\=h^{8\cdot3}=h^{24}\\\\Answer:\ \boxed{\left(\dfrac{h^{12}}{h^4}\right)^3=h^{24}}

guajiro [1.7K]3 years ago
4 0

Answer:

h^{24}

Step-by-step explanation:

(\frac{h^{12}}{h^4})^3\\ (h^8)^3\\h^{24}


When dividing two exponents (of the same bases) you subtract the exponents.  When there is an exponent to an exponent, you multiply the to exponents.

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