The table shows how the number of pepperoni

gulaghasi [49]

- - Lets solve for G.

Keep in mind: G is acting as a unknown variable, commonly used as "x"
So we need to find the variable, and then we solve for g until we get "0" for our problem.
Okay so lets start off by factoring our equation, in this case you do left first.

$3g+1*g+1=0$
Alright, now we can set out "o" as the equal to all of our factors.
$g+1=0$
And now you need to solve for that,
And you get -1 for our answer.

Final answer: g=-1

7 0

3 years ago

Read 2 more answers

Only I need help with 1,2 and three please

Mazyrski [523]

Is that the whole thing?

4 0

3 years ago

How do I solve this problem??

Luda [366]

Answer:

3/10 m^2

Step-by-step explanation:

To calculate area of a triangle we multiply height with base and then divide that by 2

2/5 × 3/2 ÷ 2 = 3/10

3 0

3 years ago

What is the equation of the line with a slope of

Fofino [41]

It should be C on a Friday

5 0

2 years ago

Consider testing H^0: u=20 against H^a: u<20 where u is the mean number of latex gloves used per week by all hospital employe

iragen [17]

Answer:

Part a: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=46-1=45$

Since is a one sided test the p value would be:

$p_v =P(t_{(45)}$

Part b: Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.

a. There is insufficient evidence to reject h^0

Step-by-step explanation:

Data given and notation

$\bar X=19.1$ represent the sample mean

$s=11.8$ represent the sample standard deviation

$n=46$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is lower than 20, the system of hypothesis would be:

Null hypothesis: $\mu \geq 20$

Alternative hypothesis: $\mu < 20$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{19.1-20}{\frac{11.8}{\sqrt{46}}}=-0.517$

Part a: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=46-1=45$

Since is a one sided test the p value would be:

$p_v =P(t_{(45)}$

Part b: Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.

a. There is insufficient evidence to reject h^0

5 0

3 years ago