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3 years ago

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A key part of enabling the JVM to locate and call method main to begin the app’s execution is the ________ keyword, which indica

tes that main can be called without first creating an object of the class in which the method is declared.

Computers and Technology

1 answer:

skelet666 [1.2K]3 years ago

8 0

Answer: static

Explanation:

In java we have the static keyword to indicate that it can be called without creating an object of the class.

example :

public static void main(String arg[])

So, main can be called without creating an object of the class.

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Write is an I.P.O cycle? Describe with figure

lord [1]

Answer:

IPO refers to Input, Output and Process. As the title suggests, the IPO cycle is the input & output after the process of the information. People must give input first to get output, and then the input must be processed to get the desired outcome

7 0

3 years ago

Radio spectrum is the part of the complete range of electromagnetic waves that is used for radio communication from

Ipatiy [6.2K]

Answer:

Radio spectrum is the part of the electromagnetic spectrum ranging from 1 Hz to 3000 GHz.

Radio waves are EM (Electromagnetic)waves that have wavelengths between 1 millimeter and 100 kilometers (or 300 GHz and 3 kHz in frequency).

So I'm thinking the answer might be 3 kHz to 300 GHz.

7 0

3 years ago

Find the inverse function of f(x)= 1+squareroot of 1+2x

Svetllana [295]

Answer:

Therefore the inverse function of $f(x)=1+\sqrt{1+2x}$ is $\frac{x^2-2x}{2}$

Explanation:

We need to find the inverse of function $f(x)=1+\sqrt{1+2x}$

Function Inverse definition :

$\mathrm{If\:a\:function\:f\left(x\right)\:is\:mapping\:x\:to\:y,\:then\:the\:inverse\:functionof\:f\left(x\right)\:maps\:y\:back\:to\:x.}$

$y=1+\sqrt{1+2x}$ $\mathrm{Interchange\:the\:variables}\:x\:\mathrm{and}\:y$

$x=1+\sqrt{1+2y}$

$\mathrm{Solve}\:x=1+\sqrt{1+2y}\:\mathrm{for}\:y$

$\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}$

$1+\sqrt{1+2y}-1=x-1$

Simplify

$\sqrt{1+2y}=x-1$

$\mathrm{Square\:both\:sides}$

$\left(\sqrt{1+2y}\right)^2=\left(x-1\right)^2$

$\mathrm{Expand\:}\left(\sqrt{1+2y}\right)^2:\quad 1+2y$

$\mathrm{Expand\:}\left(x-1\right)^2:\quad x^2-2x+1$

$1+2y=x^2-2x+1$

$\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}$

$1+2y-1=x^2-2x+1-1$

$\mathrm{Simplify}$

$2y=x^2-2x$

$\mathrm{Divide\:both\:sides\:by\:}2$

$\frac{2y}{2}=\frac{x^2}{2}-\frac{2x}{2}$

$\mathrm{Simplify}$

$y=\frac{x^2-2x}{2}$

Therefore the inverse function of $f(x)=1+\sqrt{1+2x}$ is $\frac{x^2-2x}{2}$

4 0

3 years ago

What coding scheme is used by most microcomputers?

Mrrafil [7]

The answer to your question is ISYS

3 0

3 years ago

g Suppose the vertex data is stored in an array named verts and each vertex uses a list to store the coordinates. Write the code

kodGreya [7K]

Answer:

function createAndFillBufferObject(gl, data) {

var buffer_id;

// Create a buffer object

buffer_id = gl.createBuffer();

if (!buffer_id) {

out.displayError('Failed to create the buffer object for ' + model_name);

return null;

}

// Make the buffer object the active buffer.

gl.bindBuffer(gl.ARRAY_BUFFER, buffer_id);

// Upload the data for this buffer object to the GPU.

gl.bufferData(gl.ARRAY_BUFFER, data, gl.STATIC_DRAW);

return buffer_id;

}

3 0

3 years ago