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3 years ago

Quadrilateral OPQR is inscribed in circle N, as shown below. What is the measure of ∠PQR? (5 points)

Mathematics

1 answer:

dimulka [17.4K]3 years ago

7 0

Answer:

is there a picture?

Step-by-step explanation:

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Find x a) 21 √2 b)7 c)21 √2/2 d)21 √3/2

fgiga [73]

Answer:

Step-by-step explanation:

Use the sine ratio in the left, right triangle to find the common side to both triangles and the exact values

sin60° = $\frac{\sqrt{3} }{2}$ , cos45° = $\frac{1}{\sqrt{2} }$ , thus

sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{opp}{7\sqrt{3} }$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

2 × opp = 21 ( divide both sides by 2 )

opp = $\frac{21}{2}$

Now consider the right triangle on the right, using the cosine ratio

cos45° = $\frac{adjacent}{hypotenuse}$ = $\frac{\frac{21}{2} }{x}$ = $\frac{1}{\sqrt{2} }$ ( cross- multiply )

x = $\frac{21}{2}$ × $\sqrt{2}$ = $\frac{21\sqrt{2} }{2}$ → C

5 0

2 years ago

Help plz this is due today

In-s [12.5K]

Answer:

All three are similar!

Step-by-step explanation:

If you get that right, follow Sammy Revv on Spotify!

5 0

3 years ago

Read 2 more answers

Help with this question, please!! I need some help ASAP!

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

C is the most logical answer

6 0

3 years ago

Find the equation of the line that cuts through (0,5) and (1,2)?

MArishka [77]

The equation of the line that cuts through (0,5) and (1,2) is y = -3x + 5

<h3>Solution:</h3>

Given that we have to find equation of the line that cuts through (0,5) and (1,2)

The equation of line passing through points $(x_1, y_1)$ and $(x_2, y_2)$ is given as:

$y - y_1 = m(x - x_1)$

Where "m" is the slope of line

Let us first find slope of line

The slope of line is given as:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text{ Substituting } (x_1, y_1) = (0, 5) \text{ and } (x_2, y_2) = (1, 2)$

$m=\frac{2-5}{1-0}=-3$

Thus the required equation of line is:

$y - 5 = -3(x - 0)\\\\y - 5 = -3x\\\\y = -3x + 5$

Thus the equation of line is found

3 0

3 years ago

ABDC is an isosceles trapezoid. Given only the choices below, which properties would you use to prove ACD ≅ BDC by SSS?

JulsSmile [24]

If the choices are the following:
The legs are congruent.
The base angles are congruent.
The bases are | |.
The diagonals are congruent.
Then , to prove ACD ≅ BDC by SSS I would use The base angles are congruent.
This is sufficient to prove the triangles are congruent.

8 0

3 years ago