Steve had 7 more than twice as many quarters as dimes. if the total value of her coins was $10.15, how many of each kind of coin
1 answer:
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Answer: (12) ∠1 = 20° (13) ∠2 = 50° (14) ∠3 = 15° (15) UV = 80° (16) AB = 40° (17) ABC <em>or</em> 180° - CD (18) BC - 140° (19) ABC = 150°
<u>Step-by-step explanation:</u>
12) (UV - ST) = ∠1
(80 - 40) = ∠1
(40) = ∠1
20 = ∠1
13) (UV + ST) = ∠2
(70 + 30) = ∠2
(100) = ∠2
50 = ∠2
14) (VB - BS) = ∠3
(60 - 30) = ∠3
(30) = ∠3
15 = ∠3
15) (UV - ST) = ∠1
(UV - 20) = 30
UV - 20 = 60
UV = 80
16) ∠1 = arc AB
∠1 = 40
arc AB = 40
17) arc AB + arc BC = arc AC
= 180 = arc CD
18) ∠1 + ∠2 + ∠3 = 180
20 + ∠2 + 20 = 180
∠2 + 40 = 180
∠2 = 140
19) ∠1 + ∠ 2 = arc ABC
∠1 + ∠2 + ∠3 = 180
arc ABC + 30 = 180
arc ABC = 150