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r-ruslan [8.4K]
3 years ago
11

Steve had 7 more than twice as many quarters as dimes. if the total value of her coins was $10.15, how many of each kind of coin

did she have?
Mathematics
1 answer:
NemiM [27]3 years ago
3 0
X=quarters, y=dimes
7+2x=y
0.25x+0.1y=10.15
we substitute the first equation into the second equation
0.25x+0.1(7+2x)=10.15
0.25x+0.7+0.2x=10.15
0.45x+0.7-0.7=10.15-0.7
0.45x=9.45
0.45x/0.45=9.45/0.45
x=21 quarters
7+2x=y, x=21
7+2(21)=y
7+42=y
y=49 dimes
check: 0.25x+0.1y=10.15 when x=21, y=49
21(0.25)=5.25 in quarters
49(0.1)=4.90 in dimes 
5.25+4.90=10.15
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Answer: (12) ∠1 = 20° (13) ∠2 = 50° (14) ∠3 = 15° (15) UV = 80° (16) AB = 40°  (17) ABC <em>or</em>  180° - CD (18) BC - 140°  (19) ABC = 150°

<u>Step-by-step explanation:</u>

12) \frac{1}{2}(UV - ST) = ∠1

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16) ∠1 = arc AB

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