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Alex73 [517]
3 years ago
7

How do I justify my answer?

Mathematics
1 answer:
vladimir2022 [97]3 years ago
7 0
Your answer would be yes, they would be parallel.

We can justify this using co-interior angles, which state that 2 angles subtended by parallel lines add up to 180°

We can check this with both angles 3x & x, or 2x & 90°.
If AD and BC are parallel, then 3x + x = 180, and since you already found the value of x we can substitute this in:
3(45) + (45) = 180
135 + 45 = 180
180 = 180

So the co-interior angles do add up to 180°, which means that AD and BC are parallel.

I hope this helps! Let me know if you have any questions :)
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the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function
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The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

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The triangles are congruent by congruency theorem SAS.

Step-by-step explanation:

Side-Angle-Side, as it suggests, is when a triangle is congruent by the order of congruent side, congruent angle, and another congruent side. If named certain ways, they can be congruent. Since the question does not provide a specific way of naming the triangles, we can assume that any way is allowed. 2.5 and 2.5 are congruent, followed by angles D and G which have the congruent angle markers. The congruent angles are followed by 1.7 and 1.7, making the triangles congruent by Side-Angle-Side.

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Arrange the pairs of points in increasing order of the slopes of the lines joining them. (15, 30) and (20, 40)
gavmur [86]

Answer: m1 = 0.5

M2= 0.375

M3 = 2.25

M4 = 3.0

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M6 = 0.285

M7 = 7.0

Step-by-step explanation:

(20,40)-(15,30)=(5,10), m1=5/10=0.5

(18,48)-(12,32)=(6,16), m2=3/8=0.375

(72,32)-(27,12)=(45,20), m3=9/4=2.25

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(24,84)-(18,63)=(6,21), m6=2/7=0.285...

(84,12)-(63,9)=(21,3), m7=7.0

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