We are given
arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103
so, first term is 124
u(1)= 124
now, we can find common difference
now, we can find kth term
now, we can plug values
and we get
u(k) must be negative
so,
now, we can solve for k
so, it's closest integer value is
..............Answer
Answer:
E
Step-by-step explanation:
Its simple
Answer:
33.89
Step-by-step explanation:
the side lengths are the distances between the corner points of the triangle.
P and Q have the same x value, and they therefore create a side parallel to the y-axis. and it is easy to find the length of this side : it is just the difference of the y values.
PQ = 6 - (-6) = 6 + 6 = 12
QR and RP are trickier.
we need Pythagoras to calculate the length of the direct connection between these points as the Hypotenuse of the right triangles with the differences in x and in y values as the other sides.
QR :
QR² = (-3 - 6)² + (-6 - -2)² = (-9)² + (-4)² = 81 + 16 = 97
QR = sqrt(97) ≈ 9.848857802
RP :
RP² = (6 - -3)² + (-2 - 6)² = 9² + (-8)² = 81 + 64 = 145
RP = sqrt(145) ≈ 12.04159458
the perimeter/circumference of the triangle is the sum of all 3 sides
= 12 + sqrt(97) + sqrt(145) ≈ 33.89
