Help me solve please.

Mathematics

1 answer:

Sophie [7]3 years ago

4 0

Answer:

r3d option to first, last option to second

Step-by-step explanation:

You might be interested in

Find fraction between 3/2 and 1/34

Salsk061 [2.6K]

The average of any two numbers lies between those two numbers:

$\dfrac{\frac32+\frac1{34}}2=\dfrac{\frac{51}{34}+\frac1{34}}2=\dfrac{\frac{52}{34}}2=\dfrac{26}{34}=\boxed{\dfrac{13}{17}}$

3 0

3 years ago

PLS HELP LOOK AT PIC

zepelin [54]

31 trust In me I learned this last week

7 0

3 years ago

Three men are trying to hold a ferocious lion still for the veterinarian. The lion, in the center,is wearing a collar with three

Andre45 [30]

The answer
<span>the third rope to counterbalance Sam and Charlie is F
and vectF +vectF1 +vectF2 =vect0
let's consider axis
y'y </span>vectF = -F
vectF 1= F1cos60
vectF 2= F2cos45
-F = -F1cos60-F2co45
so F= F1cos60+F2co45= 350x0.5+400x0.7=457.84 pounds

4 0

3 years ago

What frequency does 125/232 represent

dedylja [7]

Uh thinking itz -66/100

6 0

3 years ago

Read 2 more answers

Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am

zheka24 [161]

SOLUTION

We have been given the equation of the decay as

$\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}$

So we are looking for the time

Plugging the values into the equation, we have

$\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}$

Taking Ln of both sides, we have

$\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}$

Hence the answer is 4308 to the nearest year

8 0

9 months ago