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s2008m [1.1K]
3 years ago
5

Pls solve the equation

Mathematics
1 answer:
Olegator [25]3 years ago
8 0
Not sure but I think it is 3. If you get it wrong I am so sorry.
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Approximate the change in the volume of a sphere when its radius changes from r​ = 40 ft to r equals 40.05 ft (Upper V (r )equal
alexgriva [62]

Answer:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere (V), measured in cubic feet, is represented by the following formula:

V = \frac{4\pi}{3}\cdot r^{3}

Where r is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

\Delta V = \frac{\partial V}{\partial r}\Delta r

The derivative of the volume as a function of radius is:

\frac{\partial V}{\partial r} = 4\pi \cdot r^{2}

Then, the change in volume is expanded:

\Delta V = 4\pi \cdot r^{2}\cdot \Delta r

If r = 40\,ft and \Delta r = 40\,ft-40.05\,ft = 0.05\,ft, the change in the volume of the sphere is approximately:

\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)

\Delta V \approx 1005.310\,ft^{3}

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

7 0
3 years ago
Jacobs college savings are invested in a bond that pays an annual interest of 6.2% compounded continuously. How long will it tak
DiKsa [7]

Answer:

Therefore the value of bond will triple after 17.72 years.

Step-by-step explanation:

The formula of Compounded continuously

A=Pe^{rt}

A= Amount after t year

P= initial amount

r = rate of interest

t= time in year.

Given that,

Jacobs college saving are invested in bond that pay 6.2% compounded continuously.

Let after t years the initial amount P will be triple i.e 3P.

Here P=P, A=3P, r= 6.2%=0.062

\therefore 3P=Pe^{0.062t}

\Rightarrow 3=e^{0.062t}   [ Multiply \frac 1P both sides]

Taking ln both sides

\Rightarrow ln3=ln(e^{0.062t})

\Rightarrow ln3={0.062t}        [ since ln(e^a)=a ]

\Rightarrow t=\frac{ln3}{0.062}

\Rightarrow t\approx 17.72 years

Therefore the value of bond will triple after 17.72 years.

4 0
3 years ago
Could somebody answer this
solmaris [256]
The gradient for a parallel line is the same.
perpendicular lines are negative reciprocals.
so all you have to do is re arrange it so y=Mx+b so the check out the gradients to what I listed above... remember y shouldn't have any number on it.
3 0
3 years ago
Find the nth term of this sequence 7 12 17 22 27 ...
Scorpion4ik [409]
Im assuming you meant the 9th term and thats 47 
5 0
3 years ago
1/2 = 1/4 (×-10) how can I solve it
nikklg [1K]
Honestly just use photo math
3 0
3 years ago
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