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3 years ago

What is 125.2 X 3 3/4=?

Mathematics

1 answer:

Lilit [14]3 years ago

8 0

Answer: 31.3x33

Step-by-step explanation:

Did the test :)

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Use the ALEKS calculator to find 35% of 67. Do not round your answer.

Paha777 [63]

Answer:

23.45

Step-by-step explanation:

35 percent of 67=23.45

35×67=2345

2345/100=23.45

4 0

3 years ago

Help me pleaseeee!!!

larisa86 [58]

Answer:

5/12

Step-by-step explanation:

Hello, I am no math expert so take this with a grain of salt. Tan=Opposite/Adjacent. Side ON is opposite and side MN is Adjacent. This would mean that the ration would be 5/12. I hope that helped!

6 0

3 years ago

Read 2 more answers

A superintendent of a school district conducted a survey to find out the level of job satisfaction among teachers. Out of 53 tea

frez [133]

Answer:

b. 1.15

Step-by-step explanation:

The z statistics is given by:

$Z = \frac{X - p}{s}$

In which X is the found proportion, p is the expected proportion, and s, which is the standard error is $s = \sqrt{\frac{p(1-p)}{n}}$

Out of 53 teachers who replied to the survey, 13 claim they are satisfied with their job.

This means that $X = \frac{13}{53} = 0.2453$

She find that the proportion of satisfied teachers nationally is 18.4%.

This means that $p = 0.184$

Standard error:

p = 0.184, n = 53.

$s = \sqrt{\frac{0.184*0.816}{53}} = 0.0532$

Z-statistic:

$Z = \frac{X - p}{s}$

$Z = \frac{0.2453 - 0.184}{0.0532}$

$Z = 1.15$

The correct answer is:

b. 1.15

5 0

4 years ago

Out of 120 high school boys and 80 high school girls, 45 tried out for track. Of those 45, 12 were girls.

zhannawk [14.2K]

<span>So there are 33 boys who tried out for track. And this is 27.5 % of the total boys. And there 15% of the girls who tried out for the track. And in total 22.5 % of the total population tried out for track</span>

5 0

3 years ago

A random sample of 60 suspension helmets used by motorcycle riders and automobile race-car drivers was subjected to an impact te

pentagon [3]

Answer:

The 95% confidence interval on the true proportion of helmets of this type that would show damage from this test is (0.169, 0.397).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.