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3 years ago

F is between E and G, EF= 7, and FG= 6 . Find EG

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

4 0

Answer:

Step-by-step explanation:

Step 1:

EF + FG = EG Equation

Step 2:

7 + 6 = EG input values

AnsweR:

13 = EG Add

Hope This Helps :)

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Equation, find y when x=-3.<br><br> y = -x + 5<br><br> When x = -3, y =

Step2247 [10]

I think y = 8. Since x = -3 then the equation would be y = -1(-3) +5. -1 times -3 equals 3. So now the equation is y = 3 +5. That would give you 8.

7 0

3 years ago

There are 36 people in a fitness studio. What fraction represents the number of people running? • 3 8 of the people lifted weigh

klio [65]

Answer:

7/24

Step-by-step explanation:

3/8 is changed to 9/24 people lifting weights

1/3 is changed to 8/24 people cross training

17/24 people are not running

7/24 people are running

7/24 cannot be reduced

5 0

4 years ago

1. Two object accumulated a charge of

In-s [12.5K]

Answer:

The magnitude of the electric force between these two objects

will be: 181.274 N.

i.e. F $=181.274$ N

Step-by-step explanation:

Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8 μC = 2.8 × 10⁻⁶ C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

$F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}$

$=\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $\mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4$

$\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}$

$=\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}$

$=\frac{12.6}{0.025^2\times \:35.4\pi }$ ∵ $\left(10^{-2}\times \:2.5\right)^2=0.025^2$

$=\frac{12.6}{0.022125\pi }$ ∵ $35.4\pi\times 0.025^2=0.022125\pi$

$=\frac{12.6}{0.06950 }$

F $=181.274$ N

Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.

i.e. F $=181.274$ N

7 0

3 years ago

Please help! 30 points and crown! A diagonal of a cube measures StartRoot 750 EndRoot cm. The diagonal of a face measures StartR

rodikova [14]

Let length, width, and height be s.

Then diagonal of any face would be √( s² + s² ) = √( 2s² )

And we know that it measures √( 500 ) so that's sufficient for us to figure out the length of an edge of the cube. We do not need to worry about the diagonal of the cube.

Now we have to solve √( 500 ) = √( 2s² )

Square both sides:

500 = 2s²

Divide both sides by 2:

250 = s²

Take the square root of both sides:

√(250) = s ≈ 15.8113883

Rounding to nearest tenth:

s ≈ 15.8

Final answer: 15.8

Hope this helps.

8 0

3 years ago

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What is 928/100 simplified

enyata [817]

Answer:

232/25.

Step-by-step explanation:

7 0

3 years ago

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