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Romashka [77]
3 years ago
11

Prove that for all whole values of n the value of the expression:

Mathematics
1 answer:
marissa [1.9K]3 years ago
4 0

Expand:

n(n-1)-(n+3)(n+2)=(n^2-n)-(n^2+5n+6)=-6n-6

Then we can write

n(n-1)-(n+3)(n+2)=6\boxed{(-n-1)}

which means 6\mid n(n-1)-(n+3)(n+2) as required.

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