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4 years ago

I need help please a,bc,d I keep getting 1/6. Will give points

Mathematics

1 answer:

trapecia [35]4 years ago

8 0

I found a similar problem. It had an accompanying mural box. It is 18 by 18.

Area = 18 * 18 = 324 square units

Riley agreed to prepare 1/2 of the area = 324 square units * 1/2 = 162 square units.
Morgan agreed to clean and seal 1/3 of the area = 324 square units * 1/3 = 108 square units
Reggie agreed to finish the work on the remaining 1/6 of the area = 324 square units * 1/6 = 54 square units.

Riley completed 1/3 of his part = 162 square units * 1/3 = 54 square units
Morgan completed 5/6 of her part = 108 square units * 5/6 = 90 square units
Reggie completed 2/3 of his part = 54 square units * 2/3 = 36 square units

Completed the most mural: Morgan
Completed the least mural: Reggie

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3 years ago

For all functions of the form f(x) = ax2 + bx + c, which is true when b = 0?

Klio2033 [76]

When b=0
f(x)=ax^2+c

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4 years ago

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Solve for the indicated variable: ⅖(z + 1) = y for z.

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Answer:

z = 5/2y -1

Step-by-step explanation:

We observe that z has ...

1 added
the sum multiplied by 2/5

To solve for z, we undo these operations in reverse order.

$\dfrac{2}{5}(z+1)=y\qquad\text{given}\\\\z+1=\dfrac{5}{2}y\qquad\text{multiply by 5/2}\\\\\boxed{z=\dfrac{5}{2}y-1}\qquad\text{subtract 1}$

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3 years ago

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What fraction of a clockwise revolution does the hour hand of a clock turn through, when it goes from a) 5 to 11? b)2 to 8? c)10

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Answer: 1/2, 1/2, 1/4

Step-by-step explanation:

To find the fraction that the hour hand turns of a clockwise revolution, we have to find how long it is going then divide by 12

Ex. a) 11 - 5 = 6, 6/12 = 1/2 so the hour hand turns by 1/2 of a clockwise revolution

b) 8 - 2 = 6, 6/12 = 1/2 so the hour hand turns by 1/2 of a clockwise revolution

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2 years ago

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An accelerated life test on a large number of type-D alkaline batteries revealed that the mean life for a particular use before

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Answer:

68.2% of the batteries failed between 17.8 and 20.2 hours.

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99.97% of the batteries failed between 15.4 and 22.6 hours.

Step-by-step explanation:

The 68-95-99.7 states that, for a normally distributed sample:

68.26% of the measures are within 1 standard deviation of the sample.

95.44% of the measures are within 2 standard deviations of the sample.

99.97% of the measures are within 3 standard deviations of the sample.

In this problem, we have that:

Mean of 19 hours, standard deviation of 1.2 hours.

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This is within 1 standard deviation of the mean. So 68.2% of the batteries failed between 17.8 and 20.2 hours.

About 95.44% of the batteries failed between what two values?

This is within 2 standard deviations of the mean. So 95.44% of the batteries failed between 16.6 and 21.4 hours.

About 99.97% of the batteries failed between what two values?

This is within 3 standard deviations of the mean. So 99.97% of the batteries failed between 15.4 and 22.6 hours.

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3 years ago

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