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Anna11 [10]
2 years ago
10

HELP ILL GIVE BRAINLIEST QUICK!!

Mathematics
1 answer:
Semenov [28]2 years ago
3 0

Answer:

Dan is correct

Step-by-step explanation:

First, I calculated the amount of hours that the graph shows in total, coming up with a total of 3,085 hours. I do this by multiplying the number of adults surveyed by the number of hours they spent. So for the first column, (80+70)*1, second column, (90+80)*2, third column, (135+130)*3, fourth column, (140+135)*4, and fifth column, (65+75)*5 if you get what I mean. Then I add up all values. Knowing that there were two sets of 500 American adults interviewed already, I came to the conclusion that 1,000 total adults were surveyed. Finally, I divided the total number of hours(3,085) by the total number of adults interviewed (1,000) to get a mean of 3.085 hours, rounding it to 3 hours and proving that Dan is correct.

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Step-by-step explanation:

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The number of people who purchased a new car from force motor company , is 140% of the number of people who purchased a new car
valentinak56 [21]
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Mandi learned that each 10% of charge on her cell phone gave her an hour and twenty minutes of use. While playing a game today o
Sonja [21]

Answer:

3hrs 12 mins

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For every 10% charge she gets 1hr 20mins (or 80 mins)

Charge drop = (81% - 57%) = 24%

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          24% gives (24/10) x 80 mins = 192 mins

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3 0
3 years ago
If x = a cosθ and y = b sinθ , find second derivative
Olin [163]

I'm guessing the second derivative is for <em>y</em> with respect to <em>x</em>, i.e.

\dfrac{\mathrm d^2y}{\mathrm dx^2}

Compute the first derivative. By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}

We have

y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta

x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta

and so

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta

Now compute the second derivative. Notice that \frac{\mathrm dy}{\mathrm dx} is a function of \theta; so denote it by f(\theta). Then

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}

By the chain rule,

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}

We have

f=-\dfrac ba\cot\theta\implies\dfrac{\mathrm df}{\mathrm d\theta}=\dfrac ba\csc^2\theta

and so the second derivative is

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac ba\csc^2\theta}{-a\sin\theta}=-\dfrac b{a^2}\csc^3\theta

4 0
3 years ago
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