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nataly862011 [7]
2 years ago
8

Rena wrote all the integers from 1 to 12. How many digits did she write?

Mathematics
1 answer:
belka [17]2 years ago
5 0

Answer:

she wrote 10 integers.

Step-by-step explanation:

2, 3, 4, 5, 6, 7, 8, 9, 10, 11

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Which rule explains why these triangles aren't congruent? see picture below.
Lisa [10]

Answer:

SSS

Step-by-step explanation:

Well, the picture says asks why the triangles are congruent but your question asks why they aren't congruent, so I will just assume that you made a typo, and you really meant: "Which rule explains why these triangles are congruent?"

Well, the triangles have two congruent sides, and they have a common shared side that are both congruent (due to reflexive property), so the triangle theorem SSS (Side-Side-Side) proves that the triangles are both congruent.

7 0
3 years ago
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
2 years ago
Read 2 more answers
3. Solve: 3(x + 3) &gt; 4(x - 4) A. x &gt; 25 B. x &lt; 25 C. X &gt; - 7 D. x &lt; -7<br>explain​
Paha777 [63]

Answer:

B.x<25

Step-by-step explanation:

Let's solve your inequality step-by-step.

3(x+3)>4(x−4)

Step 1: Simplify both sides of the inequality.

3x+9>4x−16

Step 2: Subtract 4x from both sides.

3x+9−4x>4x−16−4x

−x+9>−16

Step 3: Subtract 9 from both sides.

−x+9−9>−16−9

−x>−25

Step 4: Divide both sides by -1.

−x/ −1 > −25/ −1

x<25

Answer:

x<25

7 0
2 years ago
N-6=4n+3+4+11<br><img src="https://tex.z-dn.net/?f=n%20-%206%20%3D%204n%20%2B%203%20%2B%204%20%2B%2011" id="TexFormula1" title="
Zigmanuir [339]
Simplify the equation to n-6=4n+18
subtract 4n from both sides
n-6-4n=4n+18-4n
-3n-6=18
add 6 to both sides
-3n-6+6=18+6
-3n=24
divide both sides by -3
-3n/3=24/-3.
n=-8
hope this helps!
7 0
3 years ago
Which number belongs to the set of rational numbers and the set of integers?
professor190 [17]

-12 is an integer number, and you can write it as {-12}{1}

7.3 is a rational number, and you can write is as {73}{10}

0.41 is a rational number, and you can write is as {41}{100}

6 is a whole number, and you can write it as {6}{1}

3 1/2 is a rational number, and you can write is as

3+{1}{2}={6}{2}+{1}{2}={7}{2}

Hopes this helps also will you mind giving me brainliest?

5 0
2 years ago
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