Answer:
![x(\sqrt[12]{x^5} )](https://tex.z-dn.net/?f=x%28%5Csqrt%5B12%5D%7Bx%5E5%7D%20%29)
Step-by-step explanation:
We need to remember 2 rules when doing these:
1. ![\sqrt[n]{x^a} =x^{\frac{a}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ea%7D%20%3Dx%5E%7B%5Cfrac%7Ba%7D%7Bn%7D%7D)
2. 
Using these 2 rules, we can simplify the product (steps shown below):
![\sqrt[3]{x^2} *\sqrt[4]{x^3} \\=x^{\frac{2}{3}}*x^{\frac{3}{4}}\\=x^{\frac{2}{3}+\frac{3}{4}}\\=x^{\frac{17}{12}}\\=x^{\frac{12}{12}+\frac{5}{12}}\\=x(x^{\frac{5}{12}})\\=x(\sqrt[12]{x^5} )](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D%20%2A%5Csqrt%5B4%5D%7Bx%5E3%7D%20%5C%5C%3Dx%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%2Ax%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%5C%5C%3Dx%5E%7B%5Cfrac%7B2%7D%7B3%7D%2B%5Cfrac%7B3%7D%7B4%7D%7D%5C%5C%3Dx%5E%7B%5Cfrac%7B17%7D%7B12%7D%7D%5C%5C%3Dx%5E%7B%5Cfrac%7B12%7D%7B12%7D%2B%5Cfrac%7B5%7D%7B12%7D%7D%5C%5C%3Dx%28x%5E%7B%5Cfrac%7B5%7D%7B12%7D%7D%29%5C%5C%3Dx%28%5Csqrt%5B12%5D%7Bx%5E5%7D%20%29)
Rearranging, we see that it is the third choice.
Is this a STARR test?
A. Divide 99 by 250
Answer:
Step-by-step explanation:
time taken to reach the max height is expressed according to the projectile equation;
tmax = u/g
Given u = 30m/s
g is the acceleration due to gravity = 9.81
t = 30/9.81
t = 3.0secs
hence it will take the flare 3.06secs to reach its maximum height.
Max height = u²/2g
Max height = 30²/2(9.81)
Max height = 900/19.62
Max height = 45.87m
If the people set off an emergency flare from a height of 2 meters above the water, the total height will be 45.87 + 2 = 47.87m
Answer:
On the 12th day
Step-by-step explanation:
12 is a multiple of both 4 and 6
X| 2|4|6jsososodidididjfjfifififififofioff
