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Dovator [93]
3 years ago
12

This question is 87 points. this is a lot of points. use it wisely. respect the point.

Mathematics
2 answers:
cupoosta [38]3 years ago
8 0
Hey hey hey hey hey hey hey
Furkat [3]3 years ago
5 0

Answer:

i will respect the points

Step-by-step explanation:

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hichkok12 [17]

Answer:

A. 108 in^2

B. 144 in^2

C. 36 in^2

Step-by-step explanation:

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2 years ago
Pls help<br> Will mark you brainliest :)
jeyben [28]

Answer:10

Step-by-step explanation:

7 0
3 years ago
Differentiate between interest and interest rate​
vodka [1.7K]

Answer:

<h3 /><h3><em>Interest:</em></h3>

<em>Interest is the cost of borrowing money, and the money you earn from your savings.</em>

<h3 /><h3><em>Interest rate</em></h3>

<em>Interest rates indicate this cost or return as a percentage of the amount you are borrowing or lending (since you are “lending” your savings to the </em><em>bank)</em>

<h3><em>❤</em><em>◍</em><em> </em><em>jess </em><em>bregoli</em><em> </em><em>◍❤</em></h3>

#<em>k</em><em>e</em><em>e</em><em>p</em><em> </em><em>learning</em><em>!</em><em>!</em>

5 0
3 years ago
Someone help 9th grade math i will give brainliest
DENIUS [597]

Answer:

I think it may be H. but let me know if i am wrong. if i am right plz mark brainliest

Step-by-step explanation:

27 divided by 3 is 9, 27/3=9 because 27/3 is the same exact thing as 27 divided by 3. So the answer has to be 9

6 0
3 years ago
Determine whether each expression can be used to find the length of side AB. Match Yes or No for each
tankabanditka [31]

Answer:

(a)\ AB = \frac{7}{\sin (B)}  \to Yes

(b)\ AB = \frac{24}{\cos (B)} \to Yes

(c)\ AB = \frac{24}{\cos (A)} \to No

(d)\ AB = \frac{7}{\cos (A)}  \to Yes

Step-by-step explanation:

Given

BC =24

AC = 7

Required

Select Yes or No for the given options

(a)\ AB = \frac{7}{\sin (B)}  \to Yes

Considering the sine of angle B, we have:

\sin(B) = \frac{Opposite}{Hypotenuse}

\sin(B) = \frac{7}{AB}

Make AB, the subject

AB = \frac{7}{\sin(B)}

(b)\ AB = \frac{24}{\cos (B)} \to Yes

Considering the cosine of angle B, we have:

\cos(B) = \frac{Adjacent}{Hypotenuse}

\cos(B) = \frac{24}{AB}

Make AB the subject

AB = \frac{24}{\cos(B)}

(c)\ AB = \frac{24}{\cos (A)} \to No

Considering the cosine of angle B, we have:

\cos(A) = \frac{Adjacent}{Hypotenuse}

\cos(A) = \frac{7}{AB}

Make AB the subject

AB = \frac{7}{\cos(A)}

(d)\ AB = \frac{7}{\cos (A)}  \to Yes

<em>This has been shown in (c) above</em>

3 0
3 years ago
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