All categories

3 years ago

Is 9-z polynomial ?

Mathematics

1 answer:

storchak [24]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

Eastside middle school has 1,500 students. Thirty-two percent of them are in sixth grade. How many sixth-grade students are the

hichkok12 [17]

480 six graders
1,500*0.32 = 480

6 0

3 years ago

Calculating area of rectangle

PSYCHO15rus [73]

Answer:

$Area = 216.108cm^2$ --- You

$Area = 216.940cm^2$ --- Another student

Reason: Because there is a variation in the given dimensions

Step-by-step explanation:

Given

Your measurement

$Length = 20.70cm; Width =10.44cm$

Another students'

$Length = 20.74cm; Width =10.46cm$

Solving (a): The area

Area is calculated as:

$Area = Length * Width$

For you

$Area = 20.70cm * 10.44cm$

$Area = 216.108cm^2$

For the other student

$Area = 20.74cm * 10.46cm$

$Area = 216.940cm^2$

Solving (b): Reason for the variation in the areas

The given measurements are estimates of the dimensions of the rectangle.

Since there is a variation in the estimates, there will be some level of variation in the calculated area.

4 0

3 years ago

6. Mary worked 27 hours last week. If she gets paid $12/hour, what is her gross pay?

kupik [55]

Answer:

324

Step-by-step explanation:

you would multiply 27 × 12 and that would equal 324

8 0

3 years ago

Pedro bought lb of red sand and lb of brown sand to refill his sand box. Both types of sand cost $4.60 a pound. How much did Ped

Doss [256]

If we know that Pedro bought 1 $\frac{1}{4}$ pounds of red sand, and 5 $\frac{1}{2}$ pounds of brown sand, and they both cost $4.60, then we just have to add the individual amounts of sand, since they cost the same.

$1 \frac{1}{4} + 5 \frac{1}{2} = 6 \frac{3}{4}$

So Pedro bought $6 \frac{3}{4}$ lbs of sand overall. Now, we just need to multiply the cost per pound by the total amount of sand he bought.

$6 \frac{3}{4} * 4.6 = 31.05$

Pedro spent $31.05 on sand, which is answer choice B.
Hope that helped =)

4 0

3 years ago

Read 2 more answers

If x > 0 and y > 0, where is the point (x, y) located?

Scrat [10]

Given, x > 0, y > 0.
So, the values of x and y are less than 0, that means, they are negative integers.
If we divide a Cartesian plane with the x-axis and y-axis, we get four quadrants.
1st Quadrant : (+,+)
2nd Quadrant : (-,+)
3rd Quadrant : (-,-)
4th Quadrant : (+,-)
Since the values of x and y are both negative, so (x, y) is located in the 3rd Quadrant.

Hope you could get an idea from here.

Doubt clarification - use comment section

8 0

2 years ago