Which is the focus of a parabola with equation y^2=4x
2 answers:
Answer:
focus is (1,0)
Step-by-step explanation:
the focus of a parabola with equation
Focus point lies inside the parabola
To find the focus of a parabola we need to find the vertex
the distance between the focus and vertex is the value of p.
Focus point is (h+p,k)
Where (h,k) is the vertex
Given equation is in the form of
Given equation can be written as
So the vertex is (0,0)
Now we find the value of p
So
Focus is (h+p,k) that is (1,0)
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Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
