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n200080 [17]
3 years ago
9

For which equation is m = 12 the solution? a. 4m=40 b. m+20=42. c. 4m=48. d. m-4=9

Mathematics
2 answers:
Gelneren [198K]3 years ago
6 0
To solve this question, we just need to insert 12 into the m position of each question and see if the equation holds true.

a. 4m = 40

4(12) = 40

48 = 40

48 obviously does not equal 40, so it is not choice A.

b. m + 20 = 42

12 + 20 = 42

32 = 42

Again, 32 isn't the same as 42, so not choice B either.

c. 4m = 48

4(12) = 48

48 = 48

It looks like this one is true, but let's solve D also just to make sure.

d. m - 4 = 9

12 - 4 = 9

8 = 9

This is false, since 8 does not equal 9.

Therefore, choice C (4m = 48) is the correct answer.
Hope that helped! =)
lys-0071 [83]3 years ago
4 0
C. 4m=48 because 48 divided by 4 is 12
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$420.25

Step-by-step explanation:

Total earnings of the week

= 400 + 3 \% \: of \:675 \\  \\  = 400 + 0.03 \times 675 \\  \\  = 400 + 20.25 \\  \\  = \$ 420.25

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7 0
2 years ago
I need help on this question
rosijanka [135]

Answer:

11. Volume = 2181.2mm^3

12. Surface Area = 1204.49mm^2

Step-by-step explanation:

We first need to find the hypotenuse side of the triangle using the Pythagorean theorem:

a^2+b^2 = c^2

13.3^2+20.5^2 = c^2

176.89+420.25 = c^2

597.14 = c^2

24.44 = c

Now we can find the volume using the formula:

V = 1/4(16)sqrt-13.3^4+2(13.3*20.5)^2+2(13.3*24.44)^2

-20.5^4+2(20.5*24.44)^2-24.44^4

V = 2181.2mm^3

To find the surface area using the surface area formula:

A = (13.3*16)+(20.5*16)+(24.44*16)+1/2sqrt

13.3^4+2(13.3*20.5)^2+2(13.3*24.44)^2

-20.5^4+2(20.5*24.44)^2-24.44^4

A = 1204.49mm^2

7 0
3 years ago
To rent a certain meeting room, a college charges a reservation fee of $41 and an additional fee of $7.90 per hour. The chemistr
Lemur [1.5K]

Answer:

41

Step-by-step explanation:

Rounding

Your cost just for the room is 41

You pay 7.90 for Your hours of being there

And your Budget is 96.30

the equation wants you for figure how many hours would you be there at the establishment that you would pay your full budget 96.30 or closer and You would only pay 41.00

4 0
3 years ago
..................................
yanalaym [24]

Answer:

The answer is a² .

Step-by-step explanation:

You have to substitute x and y into the expression :

let \: x = a \cos(θ) \\ let \: y = a \sin( θ)

{x}^{2}  +  {y}^{2}  =  {(a \cosθ )}^{2}  +  {(a \sinθ) }^{2}

{x}^{2}  +  {y}^{2}  =  {a}^{2}( {cos}^{2}θ) +  {a}^{2} ({sin}^{2}θ)

Next, you have to apply Basic Trigonometric Identity :

{sin}^{2} θ +  {cos}^{2} θ = 1

{x}^{2}  +  {y}^{2}  =  {a}^{2} ( {cos}^{2} θ +  {sin}^{2} θ)

{x}^{2}  +  {y}^{2}  =  {a}^{2} (1)

{x}^{2}  +  {y}^{2}  =  { a}^{2}

8 0
3 years ago
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