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il63 [147K]
3 years ago
13

Simplify: (12x3y4)(5x6y3)

Mathematics
2 answers:
grigory [225]3 years ago
4 0

This should be the answer I broke it down for you.

maw [93]3 years ago
4 0

Answer:

60x^9 y^7

Step-by-step explanation:

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Given: x+2y=-6. Solve for y. y=x-6/2
Snowcat [4.5K]
x+2y=-6\\\\2y=-6-x\quad|:2\\\\y=\dfrac{-6-x}{2}\\\\\\\boxed{y=-3-\frac{x}{2}}
5 0
3 years ago
This is geometry please
solmaris [256]

Step-by-step explanation:

y = 7/4 X

...... ... ... ...

6 0
2 years ago
Which best describes the graph of g(x) = 1/9 sq x<br> PICTURE DOWN BELOW
Alexus [3.1K]

Answer:

A) The graph of g(x) is shrunk vertically by a factor of 1/9

Step-by-step explanation:

The given graph g(x) = 1/9√x

f(x) = √x

The altitude of g(x) = 1/9

The altitude of f(X) = 1

When comparing the graph of g(x) with f(x), the graph of g(x) shrunk by 1/9 because of the altitude.

Here with I have attached the graph.

Therefore, answer: A) The graph of g(x) is shrunk vertically by a factor of 1/9

Thank you.

8 0
3 years ago
Whats the value of the 5 in 453,193
Nataly [62]
453,193  400,000+ 50,000 +3,000+ 100 +90+ 3=453,193 so it is ten thousand 10,000=50,000
6 0
3 years ago
Read 2 more answers
Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term,a and the common ratio,r.
Alona [7]

Answer:

Of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

Step-by-step explanation:

Recall that the direct formula of a geometric sequence is given by:

\displaystyle T_ n = ar^{n-1}

Where <em>T</em>ₙ<em> </em>is the <em>n</em>th term, <em>a</em> is the initial term, and <em>r</em> is the common ratio.

We are given that the fifth term <em>T</em>₅ = 96 and the eighth term <em>T</em>₈ = 768. In other words:

\displaystyle T_5 = a r^{(5) - 1} \text{ and } T_8 = ar^{(8)-1}

Substitute and simplify:

\displaystyle 96 = ar^4 \text{ and } 768 = ar^7

We can rewrite the second equation as:

\displaystyle 768 = (ar^4) \cdot r^3

Substitute:

\displaystyle 768 = (96) r^3

Hence:

\displaystyle r = \sqrt[3]{\frac{768}{96}} = \sqrt[3]{8} = 2

So, the common ratio <em>r</em> is two.

Using the first equation, we can solve for the initial term:

\displaystyle \begin{aligned} 96 &= ar^4 \\ ar^4 &= 96 \\ a(2)^4 &= 96 \\ 16a &= 96 \\ a &= 6 \end{aligned}

In conclusion, of the given geometric sequence, the first term <em>a</em> is 6 and its common ratio <em>r</em> is 2.

7 0
2 years ago
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