Simply get the value of the angle and distribute away.
![\bf 3[cos(270^o)+i~sin(270^o)\implies 3[0+i( -1)]\implies 3-3i](https://tex.z-dn.net/?f=%5Cbf%203%5Bcos%28270%5Eo%29%2Bi~sin%28270%5Eo%29%5Cimplies%203%5B0%2Bi%28%20-1%29%5D%5Cimplies%203-3i)
David measured the height of a window frame as 5.61 feet, but the actual height was 6 feet. What is the percentage of error in D
2 answers:
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Answer:
The answer is: 3
Step-by-step explanation:
1. At the begining of the program we start by declairing the variables:
double x=1, double y=1 and int i=0.
2. The structure do...while is used to defined the loop. x<2.5 is the finalization condition of the loop. i is the counter of the loop.
y=x/2 is the first calculation
x=x+y is the second one. Here is where the values of the variable x changes.
a) for the first iteration, the values of y and x are shown below:
The variable x is minor to 2.5 so the loop will continue computing.
b) the second iteration, the values of y and x are shown below::
The variable x is still minor to 2.5 so the loop will continue computing.
c) third iteration:
The condition x<2.5 is not true so the loop ends.
3. System.out.print(i + " "); displays the value of the variable i wich value is 3.
Therefore the number 3 is display.