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3 years ago

10

What happens to the circumference of a circle when the radius is quadrupled?

2 answers:

kogti [31]3 years ago

6 0

He circumference of a circle<span> is equal to the diameter times pi. So, let's look at </span>what happens<span> if you double the </span>radius<span> of a </span>circle<span> -- say from 2 to 4. The area will go from 12.56 to 50.24. This means that it has </span>quadrupled<span>.</span>

Zolol [24]3 years ago

5 0

Circumference = 2 * PI * radius
The circumference would also be quadrupled.
There is a direct relationship between circumference and radius.

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Avaluate 2^3x-1 for x=1

DENIUS [597]

<em><u>Answer:</u></em>

4 or 7 (Check the explanation to see which one your equation <em>actually</em> is.

<em><u>Step-by-step explanation:</u></em>

One thing I want to clarify for you, It's Evaluate, not Avaluate.

Okay so, we want to find the value of 2^3x-1 and we know x = 1.

You didn't really clarify if the expression was $2^{3x-1}$ or $2^{3x}-1$ , so I'll be doing both:

For $2^{3x-1}$ , we should plug in x to get $2^{3(1)-1}$ and then simplify to get $2^{2}$ .

2 to the power of 2 or $2^{2}$ is equal to 2 * 2 or 4.

The second one, $2^{3x}-1$ , we should plug in x to get $2^{3(1)}-1$ and then to become $2^{3}-1$ . 2 to the power of 3 or $2^{3}$ is 8 and then minus 1 is 7.

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rusak2 [61]

Answer:

$P_{m}=(6,10.5,9)$

Step-by-step explanation:

The mid point can be found with the formula

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Replacing coordinates in the formula, we have

$P_{m}=(\frac{5+7}{2},\frac{10+11 }{2} ,\frac{8+10}{2} )=(\frac{12}{2},\frac{21 }{2} ,\frac{18}{2} )\\P_{m}=(6,10.5,9)$

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Step-by-step explanation:

we know that

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see the attached figure to better understand the problem

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