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3 years ago

What happens to the circumference of a circle when the radius is quadrupled?

2 answers:

6 0

He circumference of a circle is equal to the diameter times pi. So, let's look at what happens if you double the radius of a circle -- say from 2 to 4. The area will go from 12.56 to 50.24. This means that it has quadrupled.

Zolol [24]3 years ago

5 0

Circumference = 2 * PI * radius
The circumference would also be quadrupled.
There is a direct relationship between circumference and radius.

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Hannah is giving her sister a softball for her birthday, and wants to put it in a cubic gift box to preserve the surprise. She w

Inga [223]

Answer:

B. E(s) = s^3 - 29.

Step-by-step explanation:

The amount of empty space $E(s)$ inside the cubic box is equal to the volume of the box minus the volume of the softball.

If the side length of the cubic box is $s$ , and the volume of the softball is $29in^3$ , then the amount of empty space $E(s)$ inside is

$E(s) = s^3-29$ ,

where $s^3$ is the volume of the cubic box.

Since it matches the equation we got above, choice B stands correct.

4 0

3 years ago

Which relation describes a function?

Kisachek [45]

Answer:

{(-2, -3), (-3, -2), (2,3), (3, 2)}

Step-by-step explanation:

A function is a set of ordered pairs in which no two pairs have the same first number.

In other words, an x cannot be paired with two y's.

A function takes an x and pairs it with one and only one y.

{(0,0), (0, 2), (2.0), (2, 2)} is not a function because it pairs 0 with both 0 and 2.

{(2,-1), (2, 1), (3,-1), (3, 1)} is not a function because it pairs 2 with both -1 and 1.

{(2, 2), (2, 3), (3, 2), (3, 3)} is not a function because it pairs 2 with both 2 and 3.

8 0

4 years ago

Read 2 more answers

How to do multiplicities

victus00 [196]

I think, you just find a number that could be divided by or divided for.

4 0

4 years ago

Y^3-9y^2+y-9 I don't know how to solve this can you help

aleksley [76]

I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?

In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0 and (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.

So you're final answer should be y = i and 9

3 0

3 years ago

What is the volume of the prism? enter your awnser in the box as a mixed number in simplist form

liberstina [14]

Answer:

67 1/2 is a mixed number

Step-by-step explanation:

The volume of a prism, is the area of the cross section X the length:

In this case it is base × height × length:

6 × 4.5 × 2.5 = 67.5cm^3

= 67 1 / 2 as a mixed number

4 0

3 years ago