What is the solution to the inequality below?
2 answers:
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Step-by-step explanation:
The standard form for a line is Ax+By=C
First, we need to find the slope, or change in y over change in x. For the first one, this is
, which is impossible to find as we cannot divide by 0, meaning that this is constant horizontally -- in this case, x=2. Thus, we have 1*x+0*y=2.
For the second one, we can find the slope by getting
. We can then take the point (3,0) (it can be any point on the line) and get our equation to be y-0 = (-2/3) (x-3). Converting this to standard form, we can expand this to get
y= (-2/3)*x +2
(-2/3)*x+1*y = 2
Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore,
⇒
⇒
⇒
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
Answer: There are 7,677 streets named as " First Street" and 7, 189 streets named as "Main Street" .
Step-by-step explanation:
Let x be the number of streets named as First Street .
y be the number of streets named as Main Street.
AS per the given information, we have the following system of equations :
Substitute the value of x from (2) in (1) , we get
Put value of y in (2), we get
Hence , there are 7,677 streets named as " First Street" and 7, 189 streets named as "Main Street" .