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3 years ago

Whats the LCM of 40 and 5

Mathematics

1 answer:

Simora [160]3 years ago

3 0

Answer:

The LCM of 40 and 5 is simply 40.

Step-by-step explanation:

To find the lowest common multiple of any 2 numbers, we will first list the prime factors of each number.

40: 2 × 2 × 2 × 5

5: 5

Then we need to multiply each factor the most amount of times it appears in either number.

2: 3 times in the first number

5: 1 time in either number

Now we multiply these.

2 × 2 × 2 × 5 = 40

The LCM of 40 and 5 is simply 40.

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The property of 12x2-7=6-2x2+2

gayaneshka [121]

12x2-7=6-2x2+2
14x^2-15=0
a=14 , b =0 , c=-15
0^2-4x14x(-15) =
840

6 0

2 years ago

Find the equation of the linear function represented by the table below in slope-intercept form.

Naily [24]

Question: Where is the y2? Please be more specific!

3 0

3 years ago

If the polynomial

erik [133]

Answer:

Step-by-step explanation:

<u>Given polynomial:</u>

x¹⁹ + x¹⁷ + x¹³ + x⁷ + x⁵ + x³

<u>Group as follows:</u>

(x¹⁹ + x¹⁷) + (x¹³ + x¹¹) + (x⁷ + x⁵) + (x³ + x) - x =
x¹⁷(x² + 1) + x¹¹(x² + 1) + x¹⁵(x² + 1) + x(x² + 1) - x

As we see all terms have (x² + 1) as factor apart from the last one.

It means the remainder is - x

Correct choice is C

3 0

3 years ago

Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 107°, a

Archy [21]

Answer: $105.19 \text{ square cm}$

Step-by-step explanation:

Since, by the SAS formula of finding the area of triangle,

The area of triangle, $A = \frac{1}{2}\times s_1\times s_2\times sin\theta$

Where, $s_1$ and $s_2$ are adjacent sides and $\theta$ is the included angle of these sides

Here, $s_1=22$ $s_2=10$

And, $\theta=107^{\circ}$

Thus, the area of the triangle ABC,

$A = \frac{1}{2}\times 22\times 10\times sin (107)^{\circ}$

$A = 110\times 0.95630475596$

$A = 105.193523156\approx 105.19\text { square cm}$

Therefore, Third Option is correct.

3 0

3 years ago

A bag contains 28 blue marbles and 12 red marbles. If Milton removes two marbles without replacing them, what is the probability

Ghella [55]

Answer:

A: 14/65

Step-by-step explanation:

Let A be the event of pulling a blue marble first, there are 28 blue marbles

Let B be the event of pulling a red marble second, there are 12 red marbles

There are 40 total marbles in the bag.

P(A) = 28/40

Since he pulls two marbles with out replacement, there is one less marble in the bag when he pulls the second marble, so there are only 39 marbles left, so

P(B) = 12/39

When calculating the probability of multiple events, you multiply their probabilities together, so we have

P(A then B) = (28/40)(12/39) = 336/1560

Now reduce the fraction...

112/520

28/130

14/65

8 0

3 years ago