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noname [10]
4 years ago
12

Which statement is a correct expression of the Law of Conservation of Mass?

Chemistry
1 answer:
Sedaia [141]4 years ago
6 0
Total mass stays the same
B
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Easy one giving brainly if correct + detailed​
Softa [21]
좋은 하루 되시고 도움이 되셨길 바랍니
7 0
3 years ago
Why do crisp packets become inflated at high altitudes? Again, explain in as great a detail as possible, using ideas about parti
Andrei [34K]
As you get higher the atmospheric pressure lowers. The pressure in the packet of crisps has the pressure at which it has been closed (pressure at the surface of the earth). This means that the air molecules in the packet press harder outside than the air molecules in the atmosphere press on the packet.
3 0
4 years ago
An equilibrium mixture contains 0.750 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the
sasho [114]

1.302  moles of carbon dioxide would have to be added

<h3>Further explanation</h3>

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}

While the equilibrium constant is based on partial pressure

\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}

The value of Kp and Kc can be linked to the formula '

\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}

R = gas constant = 0.0821 L.atm / mol.K

=n = number of product coefficients-number of reactant coefficients

An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O

  • We determine Kc (constant concentration)

\displaystyle Kc=\frac{0.75.0.75}{0.2.0.2}\\\\Kc=14.1

  • the amount of carbon monoxide to 0.300 mol

Reaction :

                CO +H₂O ⇔ CO₂ + H₂

initially      0.2   0.2       0.75+x  0.75

reaction    0.1    0.1        0.1         0.1

product     0.3   0.3       0.65+x    0.65

\displaystyle Kc=\frac{(0.650+x)(0.65)}{0.3.0.3}\\\\14.1(0.09)=0.4225+0.65x\\\\1.269-0.4225=0.65x\\\\0.8465=0.65x\\\\x=1.302

<h3>Learn more</h3>

an equilibrium constant brainly.com/question/9173805

brainly.com/question/1109930

Calculate the value of the equilibrium constant, Kc

brainly.com/question/3612827

Concentration of hi at equilibrium

brainly.com/question/8962129

Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient

3 0
4 years ago
Read 2 more answers
Calculate the acceleration of a car if its speed increases from 4.0 m/s to 16 m/s in 3.7 s.
ioda

Answer:

3.24m/s^2

Explanation:

The following data were obtained from the question:

U = 4m/s

V = 16m/s

t = 3.7secs

Acceleration is change in velocity with time i.e

a = (V — U) / t

a = (16 — 4) / 3.7

a = 12/3.7

a = 3.24m/s^2

8 0
3 years ago
In order for fusion to begin during the birth of a star there needs to be a certain amount of
kari74 [83]
<span>amount of heat and energy(energy of fusion)</span>
4 0
4 years ago
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