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Alenkinab [10]
3 years ago
13

How to identify reasonable domain and range​

Mathematics
1 answer:
puteri [66]3 years ago
6 0

Answer:

The domain is the input values on the x-axis and range is input values on the y-axis

Step-by-step explanation:

Basically, domain is the horizontal values and range is the vertical ones.

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Factor the expression and then evaluate without a calculator: 3·(m−4)−n·(m−4), if m=5, and n=4 : The factored expression is ___,
vlada-n [284]

Answer:

-1

Step-by-step explanation:

equation:

3(5-4)-4(5-4)

3*5-3*4 -4*5-4*-4

15-12-20+16

3-4

-1

6 0
3 years ago
b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
3 years ago
the distance between two towns on a map is 6cm. the actual distance between 2 towns is 48km what is the scale on the map​
kodGreya [7K]

Answer:

1 cm=8 km

Step-by-step explanation:

We can use a ratio to determine the scale.  Take the distance on the map  on the left and the "real distance" on the right

6 cm=48 km

Divide by 6

6 cm/ 6 = 48 km /6

1 cm=8 km

4 0
2 years ago
Triangle PQR where P(1,4), Q(-3,-4),R(7,k) is right-angled at Q. find the value of k
NikAS [45]

Answer:

k = -9.

Step-by-step explanation:

As the triangle is right-angled at Q, by Pythagoras:

PR^2 = PQ^2 + RQ^2

So, substituting the given data and using the distance formula between 2 points:

(7 - 1)^2 + (k - 4)^2 =  (-4-4)^2 + (-3-1)^2 + (7 - (-3))^2 + (k - (-4))^2

36 + (k - 4)^2 = 64 + 16 + 100 + ( k + 4)^2

(k - 4)^2 - (k + 4)^2 = 180 - 36

k^2 - 8k + 16 - (k^2 + 8k + 16) = 144

-16k = 144

k = -9.

8 0
3 years ago
Read 2 more answers
Solve.<br><br><br> k<br> 5<br> + 9 = 22<br><br> k =
mihalych1998 [28]

Answer:

Step-by-step explanation:

Here you go mate

Step 1

-3x<3  Equation/Question

Step 2

-3x<3  Simplify

-3x<3

Step 3

-3x<3  Divide by -3

Answer

x>-1

3 0
3 years ago
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