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just olya [345]
3 years ago
10

On a coordinate plane, solid circles appear at the following points: (negative 3, 2), (negative 3, 3), (1, 4), (1, negative 4),

(2, negative 4), (2, negative 2). How many points need to be removed from this graph so that it will be a function?
Mathematics
2 answers:
goldenfox [79]3 years ago
8 0

Answer: Three points

Step-by-step explanation:

(-3,2)     (-3,3)    (1,4)   (1,-4)  (2,-4)  (2,-2)

Looking at these points we could say there all doesn't represent a function because each input doesn't exactly assigns one output.

for example -3 the input assigns two different outputs  2 and 3

1  the input   also assigns two different outputs 4 and -4

and lastly 2 the input assigns two different outputs -4 and -2

This makes it not a function but if we take away the coordinates

(-3,3) ( 1,-4) and (2,-4) it becomes a function because you will have the coordinates (-3,2) (1,4) (2,-2)  and as you could see every input has exactly one output.

Elanso [62]3 years ago
4 0

Answer:

C. 3 points

Step-by-step explanation:

just took the quiz

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Step-by-step explanation:

The denominators are 2, 3, and 4.  The least common denominator is the least common multiple (LCM) of these numbers.

To find the LCM, first write the prime factorizations.

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= ²¹/₁₂ + ⁶/₁₂ + ²⁰/₁₂ + ⁴/₁₂ + ³/₁₂ + ⁶/₁₂

Now that the denominators are the same, we can simply add the numerators.

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