Given
d(t) = 0.8t ^2
t= 5 secs
d(5) = 0.8(5)^2 = 0.8 * 25 = 20
t= 10 secs
d(10) = 0.8(10)^2 = 0.8 * 100 = 80
20 m / 5 secs = 4 meters per sec
80 m / 10 sec = 8 meters per sec
4 mps + 8 mps = 12 mps
12 mps / 2 = 6 mps
6 mps is the average speed of the rock between 5 and 10 sec after being dropped
hzvvsbbdhdhsvsnsjsvsbsh sbsbbsbshdi she's sbsbbsbshdi hahaha subs shay dygd
32/48 simplified by 16 that equals 2/3
Across x = 4 -> (8,0)
Across y = -3 -> (8,-6)
