Answer:
6 ft
Step-by-step explanation:
As we know that, the arch meet the ground are the value of x when y = 0
y=−0.9(x+3)(x−3)
<=> 0 = −0.9(x+3)(x−3)
<=> x=3 or x=-3
So we have 2 coordinates: (3, 0) and (-3,0) and the distance between them is:
3 -(-3) = 6
=> The width of the arch at ground level is 6 ft
4d = 24 would be the right equation. To double check you would divide both sides by 4 (the number of legs) to find the amount of dogs.
Answer:
a3 + b3 = -7
Step-by-step explanation:
When the sequence is A.P
a1 =4 and a2= -2
Common difference,d = a2 - a1
= -2 - 4
d = -6
a3 = third term
a3 = a1 + 2d
= 4 + 2(-6)
= 4 - 12
= -8
a3 = -8
When the sequence is geometric
a1 =4 and a2= -2
Common ratio, r = a2/a1
= -2/4
r = -1/2
Or
r = -0.5
b3 = third term
b3 = ar²
= 4 * (-1/2)²
= 4 * 1/4
= 4/4
= 1
b3 = 1
a3 + b3 = -8 + 1
= -7
a3 + b3 = -7
What is the total weight of the water in the pool when it is completely filled?
V = L * W * D
V = 18 * 9 * 54/12
V = 18 * 9 * 4.5
V =729 cubic feet
729 cubic feet of water times 62.4 pounds = 45489.6 pounds
Answer:
Step-by-step explanation:
Area of sector = (∅/360°) x πr²
Area of sector = 48cm²
radius = 4cm
π = 3.14
48 = (∅/360°) x 3.14 x 4 x4
48 = (∅/360°) x 50.24
48/50.24 =(∅/360°)
0.9554 = (∅/360°)
∅ = 0.9554 x 360 = 343.949≈343.95° ( these is when the angle is in degrees)
if it is radians
area of sector = 1/2r²∅
area of sector = 48
r = radius = 4
area of sector = 1/2r²∅
48 = 1/2 x 4 x4 x∅
48 = 2x4 x∅
48 = 8∅
∅ = 48/8 = 6 radians
the central angle in radians is 6
