Please read the directions for exersizes 23 and 14. Look at attachment!!!!!
1 answer:
This is an arithmetic sequence because each term is 9 more than the previous term, called the common difference. The equation for an arithmetic sequence is: a(n)=a+d(n-1), a=initial term, d=common difference, n=term number... In this case a=9 and d=9 so a(n)=9+9(n-1) a(n)=9+9n-9 a(n)=9n So for any term n, a(n)=9n ... a(16)=9*16=144
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