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3 years ago

What is the answer and how do u do it??

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

6 0

Answer:

D. 40

Step-by-step explanation:

The information given states that 500 people were surveyed, so that means that the percentages given are percents of 500. To find how many people prefer to watch television Monday night, we need to find out what 20% of 500 is. To do that, you can convert 20% to a decimal (0.2) and multiply it by 500. The answer is 100, so 100 people prefer television on a Monday night.

Next, find how many people prefer television on a Thursday night. To do that, we need to find out what 12% of 500 is. You can do that by converting 12% to a decimal (0.12) and multiply it by 500. The answer is 60, so 60 people prefer television on a Thursday night.

Finally, since you're trying to find how many more people prefer watching television on Monday night than the number of people who prefer Thursday night, you would subtract the two groups. So, 100-60=40. The final answer is D, 40.

I really hope this helps! Feel free to ask questions. ☺

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4 years ago

Logan's e-reader sent a notification saying that he has completed 75% of the e-book.

Vika [28.1K]

Answer:

The total number of pages in the e-book is 240.

Step-by-step explanation:

Given:

Logan has completed 75%

Logan has read 180 pages

To Find:

The total number of pages in the e-book= ?

Solution:

Let X be the total number of pages on the e-book

then

=> 75% of X = 180

Now lets find the value of X

X = $\frac{180}{75\%}$

X = $\frac{180}{\frac{75}{100}}$

X = $\frac{180}{0.75}$

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3 years ago

One bag contains 3/5 kg of corn. A farmer feeds his chickens 4 bags of corn each week. How many kilograms of corn do they eat ea

saveliy_v [14]

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3 years ago

Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=

Ganezh [65]

Answer:

$y(1+x)+x-5\ln xy=C$

Step-by-step explanation:

Consider the given differential equation is

$(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1$

$(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y$

$(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx$

Taking all variables on right sides.

$(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0$

$(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0$

Let as assume,

$M=-\frac{5}{x}+1+y$ and $N=1-\frac{5}{y}+x$

Find partial derivatives $\frac{\partial M}{\partial y}$ and $\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$ and $\frac{\partial N}{\partial x}=1$

Since $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ , therefore the given differential equation is exact.

The solution of the exact differential equation is

$\int Mdx+\int N(\text{without x)}dy=C$

$\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C$

$yx-5\ln x+x+y-5\ln y=C$

$y+x+xy-5\ln x-5\ln y=C$

$y(1+x)+x-5(\ln x+\ln y)=C$

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4 years ago

Find expressions for the partial derivatives of the following functions:

nlexa [21]

Answer:

Step-by-step explanation: partial derivative is the differentiation of one variable e.g. X while leaving the values of the other variable e.g. Y

These four questions A, B, C and D have different functions separated by commas. I will not assume the commas to be something else like a plus sign.

A. f(x) = g'(x).k(y) , g'(x) + h(y)

f(y) = k'(y).g(x) , g(x) + h'(y)

B. f(x) = g'x (x+y)

f(y) = g'y (x+y) , h'y (y+z)

f(z) = h'z (y+z)

C. f(x) = f'x (xy) , f'x (zx)

f(y) = f'y (xy) , f'y (yz)

f(z) = f'z (yz) , f'z (zx)

D. f(x) = f'x (x) , g'(x) , h'x (x,y)

f(y) = h'x (x,y)

These are the partial derivative expressions for each variable in each function. You will need to pay a lot of attention to understand:

* while differentiating X alone, functions in Y which are separated by commas from the functions in X, are ignored totally because they are different questions

* In functions where X added to Y is in a bracket e.g. (x+y), to find the derivative of X, Y isn't thrown away because they are joined (by a plus sign) the derivative of X alone in this case would be f'x (x+y)

* f(x), just like g(x), simply means/represents a function in X hence f'(x) means the differentiation of all X-terms in that function

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3 years ago