9514 1404 393
Answer:
779.4 square units
Step-by-step explanation:
You seem to have several problems of this type, so we'll derive a formula for the area of an n-gon of radius r.
One central triangle will have a central angle of α = 360°/n. For example, a hexagon has a central angle of α = 360°/6 = 60°. The area of that central triangle is given by the formula ...
A = (1/2)r²sin(α)
Since there are n such triangles, the area of the n-gon is ...
A = (n/2)r²sin(360°/n)
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For a hexagon (n=6) with radius 10√3, the area is ...
A = (6/2)(10√3)²sin(360°/6) = 450√3 ≈ 779.4 . . . . square units
Answer:
cos r/q is the answer,
Step-by-step explanation:
this can be seen when you elaborate sin=opposite/hypotenus and tan=opposite/adjacent by referring to the right angle triangle .
then, apply values of adjacent dan hypotenuse to cos
Answer:
Step-by-step explanation:
Can you please provide the question
9514 1404 393
Answer:
x = 22
Step-by-step explanation:
The midsegment BF is half length of the base segment CE, so you have ...
2x = 88/2
x = 22 . . . . . divide by 2
You'll need to create two equations and have a 'system of equations' then use direct substitution to turn the equation into one. Whichever equation is easiest to solve for x or y. Solve that one for x or y and plug the result in for the variable in the other equation. Then you will have an equation with only 1 unknown.
