If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
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Y=3.25x should be the most probable choice because 6.50 is the price of 2 pounds of candy and once it’s divided by 2 the equation will show how much the unit rate is or the price of each pound of candy.
Isolate the k. Note the equal sign. What you do to one side, you do to the other.
First, subtract 2m from both sides
8k + 2m (-2m) = 3m (-2m) + 4
8k = m + 4
Next, divide 8 from both sides
(8k)/8 = (m + 4)/8
k = (m + 4)/8
k = m/8 + 1/2
k = m/8 + 1/2 is your answer
hope this helps
