For this case we have the following data:
Polynomial function of grade 5
Given roots: -2, 2,
Having an imaginary root given by 
, the other root, in the same imaginary way, must be given by its complex conjugate, that is, 
.
In this way, the fourth root is given by:
Since the polynomial function is grade 5, it must have 5 roots. Thus, the fifth root must be given by a real number.
Thus, the roots of the polynomial function are given by: three real roots and two imaginary roots.
Answer:
Option D
Answer: $22.80/hour
Step-by-step explanation: 364.80 : 16 = 22.80
The square piece of wood measures 32 in per side,
Then the circle that can be cut off it has a radius of 16 in (half of the diameter 32 in)
Therefore, the area of the circle is going to be given by the formula:
And the area of the initial square was:
Area = 32^2 in^2 = 1024 in^2
Therefore the left-overs of the piece of wood would be the difference:
1024 in^2 - 803.84 in^2
Least to greatest
1.04, 1.0494, 1.2, 1.33
We first need to find f(3).
f(3) = 2(3) + 8
f(3) = 6 + 8
f(3) = 14
We now want g(f(3)).
We know that f(3) is 14.
We also know that g(x) is 5.
As you know, 5 is a constant. No matter what the value of x is for g(x), it will not change the value of g(x).
So, g(f(3)) = g(14) = 5.
Answer: g(f(3)) = 5.
