Question

In JKL, solve for x. A.66.73 B.15.44 C.38.16 D.74.89

Answer 1

The answer is b 15.44

Answer 2

Answer:

D

Step-by-step explanation:

Using the sine ratio in the right triangle

sin27° = $\frac{opposite}{hypotenuse}$ = $\frac{KL}{JL}$ = $\frac{34}{x}$

Multiply both sides by x

x × sin27° = 34 ( divide both sides by sin27° )

x = $\frac{34}{sin27}$ ≈ 74.89 ( to 2 dec. places ) → D