A number minus one is at the most nine, or two times the number is at least twenty-four.

Nikitich [7]

V=V of cube- V pyramid= 8^3- 7^2*8/3=512-49*8/3=512-130,67=381.33 cm^3

7 0

2 years ago

For each of the following sequences, • Give a formula for the nth term in the sequence, • Give a recursive definition for the se

Andrew [12]

Answer:

(a) $n^{th} = n$

$f(1) = 1$

$f(n) = f(n-1) + 1$

(b) $n^{th} = 2^{n-1}$

$f(1) = 1$

$f(n) = f(n-1) * 2$

(c) $n^{th} = n!$

$f(1) = 1$

$f(n) = f(n-1) * n$

Step-by-step explanation:

(a) This is a sequence of consecutive number

$n^{th} = n$

$f(1) = 1$

$f(n) = f(n-1) + 1$

(b) This is a sequence of 2 to the power of n - 1. The next number is twice time of this number

$n^{th} = 2^{n-1}$

$f(1) = 1$

$f(n) = f(n-1) * 2$

(c) This is factorial sequence. Where the next number is this number multiplied by $n^{th}$

$n^{th} = n!$

$f(1) = 1$

$f(n) = f(n-1) * n$

5 0

2 years ago

THE TOPIC IS: AREA OF CIRCLES!! PLEASE HELP ME WITH THIS QUESTION!!! WHATS THE ANSWER?? I WILL GIVE YOU BRAINLIEST AND A THANKS!

Art [367]

Answer:

49π

Step-by-step explanation:

πr^2

π*7^2

49π

5 0

2 years ago

-2=12/x<br><br> pleasee answer

Alecsey [184]

Answer:

Step-by-step explanation:

6 0

2 years ago

Write a rational function that meets the following criteria:

Sliva [168]

You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2

y = (x - 3)/((x - 1)(x - 3)) + 2

5 0

3 years ago