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Lelu [443]
3 years ago
13

A number minus one is at the most nine, or two times the number is at least twenty-four.

Mathematics
1 answer:
maksim [4K]3 years ago
7 0
<span>x − 1 ≤ 9 or 2x ≥ 24</span>
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Find the values of the variables.
Jlenok [28]

Answer:

The fourth option - t = 3, y = 5

Step-by-step explanation:

-8 + t becomes -5, thus t is 3 since -8 + 3 = -5.

-12 becomes -2y - 2, so we can set these equal to each other as -2y - 2 = -12 and solve from there. Add 2 to both sides, -2y = -10, then divide by -2 on both sides, y = 5.

6 0
3 years ago
Read 2 more answers
I have no clue to what I even need to do.
Gre4nikov [31]

\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \cline{1-1} \theta =\frac{3\pi }{2}\\ s=\frac{5\pi }{2} \end{cases}\implies \cfrac{5\pi }{2}=r\cdot \cfrac{3\pi }{2}

\bf \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{3~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cdot \cfrac{5~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=r\implies \cfrac{5}{3}=r

4 0
3 years ago
A 20° sector in a circle has an area of 21.51 pi yd?.
kodGreya [7K]

Answer

____________________________________________________________

This would be 21.5π * 360 / 20 yd^2  =  1215.18 yd^2 ( using pi = 3.14)

____________________________________________________________

5 0
3 years ago
Which of the following systems of linear equations has an infinite number of solutions?
arlik [135]

Answer:

{ y = 3x + 3

{ 3x - y = 3

B

(Just did the assignment 3/23/21)

8 0
3 years ago
How do i do 3 part a ?
WINSTONCH [101]


In general the binomial expansion is


(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0


So in our case, because we want ascending powers of x we'll write,


(-3x + 1)^{11} =  {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9  + {11 \choose 3 } (-3x)^3 1^8 + ...


We need to calculate the binomial coefficients:


{11 \choose 0}  = 1


{11 \choose 1}  = 11


{11 \choose 2}  = \dfrac{11 \times 10}{2} = 55


{11 \choose 3}  = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165


(-3x+1)^{11} =  1 (-3x)^0 1^{11}  + 11(-3x)^{1} 1^{10}  + 55 (-3x)^2 1^{9}  + 165 (-3x)^3 1^8 + ...


(1-3x)^{11} =  1 -33 x + 495 3x^2 - 4455 x^3+ ...



6 0
3 years ago
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