Is this the image? If so, sorry I can't do this lol
Easy peasy
the average rate of change in section A is the slope from (1,g(1)) to (2,g(2))
the average rate of chagne in section B is the slope from (3,g(3)) to (4,g(4))
A.
section A
g(1)=4(3)^1=12
g(2)=4(3)^2=4(9)=36
slope=(36-12)/(2-1)=24/1=24
section B
g(3)=4(3)^3=4(27)=108
g(4)=4(3)^4=4(81)=324
slope=(324-108)/(4-3)=216/1=216
section A has an average rate of change of 24
section B has an average rate of change of 216
Answer:What the question?
Step-by-step explanation:
Step-by-step explanation: the 1st answer
The vertical distance is 5 + 8 = 13
the horizantal distance is 3 +3 = 6
then just do pythag therom
6^2 + 13^2 = c^2
205 = c^2
<span>√205 = c
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