You have to deal with this type of question step by step. Firstly, you can figure out all the unknown values (such as sqrt x-3), by substituting x for 19, as you are trying to figure out f(x) when x=19. Therefore:
x+2=21
sqrt(x-3)=sqrt(19-3)=sqrt 16=4
Now the equation is easier to handle:
3/21 - 4
We can write this as 3/21 - 4/1 , which equals -27/7.
Answer:
![\Huge \boxed{\mathrm{60}}](https://tex.z-dn.net/?f=%5CHuge%20%5Cboxed%7B%5Cmathrm%7B60%7D%7D)
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Step-by-step explanation:
![1+32 * 2 - 5](https://tex.z-dn.net/?f=1%2B32%20%2A%202%20-%205)
Multiplying,
![\Longrightarrow \ \ 1+64-5](https://tex.z-dn.net/?f=%5CLongrightarrow%20%5C%20%5C%20%201%2B64-5)
Adding or subtracting,
![\Longrightarrow \ \ 64-4](https://tex.z-dn.net/?f=%5CLongrightarrow%20%5C%20%5C%2064-4)
![\Longrightarrow \ \ 60](https://tex.z-dn.net/?f=%5CLongrightarrow%20%5C%20%5C%2060)
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Any fraction that can be simplified to 1/4 would work. I don't have a model to shade, but I can give you some examples. 2/8, 3/12, 4/16, 5/20... I hope this helps!
Answer:
x = 12
Step-by-step explanation:
"Using the variable x for unknown number what is five more than the quotient of a number and 6 equals 7" translates into 5 + x/6 = 7.
To solve use inverse operations.
![5 + \frac{x}{6} = 7\\\\\frac{x}{6} = 2 \\\\ x = 12](https://tex.z-dn.net/?f=5%20%2B%20%5Cfrac%7Bx%7D%7B6%7D%20%3D%207%5C%5C%5C%5C%5Cfrac%7Bx%7D%7B6%7D%20%3D%202%20%5C%5C%5C%5C%20x%20%3D%2012)