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a_sh-v [17]
3 years ago
7

Can someone please help Simple the square root 24+ square root 25

Mathematics
2 answers:
yanalaym [24]3 years ago
8 0

Answer:  5 + 2\sqrt{6}

===========================================

Work Shown:

\sqrt{24}+\sqrt{25}\\\\\sqrt{25}+\sqrt{24}\\\\\sqrt{25}+\sqrt{4*6}\\\\\sqrt{25}+\sqrt{4}*\sqrt{6} \ \ \text{see note 1}\\\\\sqrt{5^2}+\sqrt{2^2}*\sqrt{6}\\\\5+2\sqrt{6} \ \ \text{see note 2}\\\\

----------

  • Note 1:  I used the rule sqrt(x*y) = sqrt(x)*sqrt(y)
  • Note 2: The rule sqrt(x^2) = x was used, where x is nonnegative
earnstyle [38]3 years ago
4 0

Answer:

5+(2)*(sq root 6)

Step-by-step explanation:

This is pretty simple, a given is that the square root of 25 is 5, so you already have one of your numbers. Since the square root of 24 is not a perfect square, it must be reduced and then added separately to 5. The sq root of 24 is reduced to 2 multiplied by the square root of 6.

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