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Ket [755]
3 years ago
14

What is the difference between the domain and the range of a function?

Mathematics
2 answers:
Nikolay [14]3 years ago
5 0

Answer:

Step-by-step explanation:

The domain of a function is the set of input (x-) values for which the function is defined.  The range is the set of output (y-) values; often there are limitations.

For example, the sine function y = sin x is defined for all real x; for every input x, there is a corresponding output y.  The sine function has a limited range in that the minimum value of the sine is -1 and the max is +1.  There is no graph above y = -1 or below y = +1.

andreev551 [17]3 years ago
3 0

Answer:

The domain is all the x values of a function while the range is all the y values of a function.

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Does anyone know the answer for the question below.
8090 [49]

Answer: option C

Step-by-step explanation:

The diagram of the triangle is shown in the attached photo. The triangle is a right angle triangle ABC

Assuming the given angle is #,

Recalling the trigonometric ratio,

tan # = opposite / adjacent

If tan # = 4, it means

opposite / adjacent = 4/1

Therefore, opposite = 4 and adjacent = 1

Applying Pythagoras theorem,

Hypotenuse^2 = opposite ^2 + adjacent ^2

Hypotenuse = AC

Opposite = 4

Adjacent = 1

AC^2 = 4^2 + 1^2 = 17

AC = ± √17

To determine cos #, we would apply another trigonometric ratio,

Cos# = adjacent /hypotenuse

Cos# = 1/±√17

Cos # =-1 /√17 or 1/√17

8 0
3 years ago
What is -2 1/2+1 1/2​
eduard
The correct answer is -1
5 0
3 years ago
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An equation is shown below:
mart [117]
Multiple 6 with numbers inside paranthesis:
12x - 66 + 15 = 21
add 66 fhen substrack 15 from both sides :
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5 0
3 years ago
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Choose the answer. 3. (1 pt) Which is an example of the distributive property? A. 9 • (t + 5) = 9t + 45 B. 9 • (t + 5) = (t + 5)
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Calculate the missing terms of the geometric sequence ...,3072, 7,2,7, 12,.... Select all that apply.
miskamm [114]

Answer:

The missing terms are 768, 192, 48.

Step-by-step explanation:

From the given geometric sequence

First term= a_1=3072

Fifth Term= a_5=12  

The general form of a geometric sequence is:

a_n=ar^(n-1)

here a_nis the nth term, a is the first term and r is the common ratio.

We will use the general form for term 5 to calculate the value of r.

So the general form for term 5 will be

a_5=3072* r^(5-1)

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12=3072* r^4

r^4=  12/3072

r^4=  1/256

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Solving for r  

r=  1/4

Now  

a_2= ar^(2-1)

a_2=3072*r

a_2=3072*  1/4

a_2=768

a_3= ar^(3-1)

a_3=3072*r^2

a_3=3072*(1/4)^2

a_3=3072*  1/16

a_3=192

a_4= ar^(4-1)

a_4=3072*r^3

a_4=3072*(1/4)^3

a_4=3072*  1/64

a_4=48

6 0
3 years ago
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