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3 years ago

Help ASAP please! Problem is on pictures below.

Mathematics

1 answer:

Elis [28]3 years ago

7 0

Answer: figures C and D.

Explanation:

The question is which two figures have the same volume. Hence, you have to calculate the volumes of each figure until you find the two with the same volume.

1) Figure A. It is a slant cone.

Dimensions:

slant height, l = 6 cm
height, h: 5 cm
base area, b: 20 cm²

The volume of a slant cone is the same as the volume of a regular cone if the height and radius of both cones are the same.

Formula: V = (1/3)(base area)(height) = (1/3)b·h

Calculations:

V = (1/3)×20cm²×5cm = 100/3 cm³

2. Figure B. It is a right cylinder

Dimensions:

base area, b: 20 cm²
height, h: 6 cm

Formula: V = (base area)(height) = b·h

Calculations:

V = 20 cm²· 6cm = 120 cm³

3. Figure C. It is a slant cylinder.

Dimensions:

base area, b: 20 cm²
slant height, l: 6 cm
height, h: 5 cm

The volume of a slant cylinder is the same as the volume of a regular cylinder if the height and radius of both cylinders are the same.

Formula: V = (base area)(height) = b·h

Calculations:

V = 20cm² · 5cm = 100 cm³

4. Fiigure D. It is a rectangular pyramid.

Dimensions:

length, l: 6cm
base area, b: 20 cm²
height, h: 5 cm

Formula: V = (base area) (height) = b·h

Calculations:

V = 20 cm² · 5 cm = 100 cm³

→ Now, you have found the two figures with the same volume: figure C and figure D. ←

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Hey there!

To solve this problem, you first would need to solve for how much of the cake is left after Jasmine, her friend, and Jasmine's brother got their slices. Then, you would need to split the remaining amount in half to get the answer of what each parent ate. We would need to make all of the denominators the same, so let's make all of the fractions out of 12, a common denominator of 3 and 4.

$\frac{12}{12} - \frac{1}{4} - \frac{1}{4} - \frac{1}{3}$
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It can then be concluded that each parent ate $\frac{1}{12}$ of the cake, since there was $\frac{2}{12}$ remaining.

You can check this answer by adding up all of the parts we used in this problem:

$\frac{3}{12} + \frac{3}{12} + \frac{4}{12} + \frac{1}{12} + \frac{1}{12} = \frac{12}{12}$

Hope this helped you out! :-)

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