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SVETLANKA909090 [29]
3 years ago
8

Where is the removable discontinuity of f(x)=x+5/x^2+3x-10 located?

Mathematics
2 answers:
professor190 [17]3 years ago
5 0

Answer:

-5 is your answer

Step-by-step explanation:

mario62 [17]3 years ago
3 0
We are looking to find the point where the curve discontinued

Step 1: Factorise both numerator and denominator (if possible)
\frac{x+5}{ x^{2} +3x-10}= \frac{(x+5)}{(x+5)(x-2)}

Step 2: Recognise the common factor, which is (x+5)

Step 3: Equate the common factor to 0
x+5=0
x=-5

Answer: -5
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18+ (-40 =||<br> please answer
8090 [49]

It would equall 22

Subtract 18 from both sides of the inequality.

a<40−18

Subtract 18 from 40.

a<22

The result can be shown in multiple forms.

Inequality Form:

a<22

Interval Notation: (−∞,22)

4 0
3 years ago
Read 2 more answers
The diameter of a pearl is about 4 x 10-3cm and the diameter of an atom is about10-11m. How much larger than an atom is a pearl?
Ugo [173]

Answer:

  • D. 4 × 10⁶ times

Step-by-step explanation:

<u>The diameter of a pearl is </u>

  • 4 × 10⁻³cm = 4 × 10⁻⁵ m

<u>The diameter of an atom is</u>

  • 10⁻¹¹m

<u>How much larger than an atom is a pearl?</u>

  • 4 × 10⁻⁵ ÷ 10⁻¹¹ = 4 × 10⁻⁵⁺¹¹ = 4 × 10⁶ times

Correct option is D

5 0
3 years ago
ERROR ANALYSIS Describe and correct the error in
valkas [14]

Answer:

The graph should be stretched rather than become narrower.

Step-by-step explanation:

To figure this out, just create some example points.

At x = 0, your y-value will always be 0. But if you were to plug in the value 1, you would get a y-value of 1 in y=x^2, but a value of 0.5 in y=0.5x^2. If you were to plug in a value of 2, you would get a value of 4 in y=x^2, but a value of 2 in y=0.5x^2.

If you continue this pattern for a few more points, then plot them, you will see that adding a coefficient of 0.5 simply stretches the graph

3 0
2 years ago
Please answer this question and answer correctly.
svet-max [94.6K]

Answer:

C. 11

Work:

y=number of misses

x=number of scores

Points: 2x-0.5y=2(7)-0.5(6)=14-3=11

Hope this helps; please vote brainliest.

8 0
3 years ago
Which is a point on the circle whose center is (0,0) and whose radius is 5? A. (0,0)
Temka [501]

Answer:

(3,4)

Step-by-step explanation:

x^2+y^2=(5)^2

if you graph it you will see that (3,4) is on the circle

4 0
3 years ago
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