Question

Where is the removable discontinuity of f(x)=x+5/x^2+3x-10 located?

Answer 1

Answer:

-5 is your answer

Step-by-step explanation:

Answer 2

We are looking to find the point where the curve discontinued

Step 1: Factorise both numerator and denominator (if possible)
$\frac{x+5}{ x^{2} +3x-10}= \frac{(x+5)}{(x+5)(x-2)}$

Step 2: Recognise the common factor, which is $(x+5)$

Step 3: Equate the common factor to 0
$x+5=0$
$x=-5$

Answer: -5