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3 years ago

7

A) name the transversal connecting 1 and 5

1 answer:

lubasha [3.4K]3 years ago

8 0

Answer:

a) Name the transversal connecting 1 and 5. Line r b) Name the transversal connecting 7 and 14. Line q c) Name the transversal connecting 8 and 11. Line s d) Name the transversal connecting 6 and 15. Line q e) Name the transversal connecting 3 and 9. Line p

Step-by-step explanation:

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Solve for me please thank you

hammer [34]

The answer to those options is of course C

5 0

3 years ago

When solving the system of equations 3x−3y=1 and −2x+4y=2 algebraically, a good first step is to:

bearhunter [10]

Answer:

A. Multiply 3x−3y=1 by 2, and multiply −2x+4y=2 by 3.

Step-by-step explanation:

Given

$3x - 3y = 1$

$-2x+ 4y = 2$

Required

A good first step

A good first step is to eliminate x and this is done as follows:

Multiply $3x - 3y = 1$ by 2 (gotten from coefficient of x in the second equation)

Multiply $-2x+ 4y = 2$ by 3 (gotten from coefficient of x in the first equation)

This gives:

$6x - 6y = 2$

$-6x + 12y = 6$

Add both equations

$6x - 6x - 6y + 12y = 2 + 6$

$6y = 8$

$y = \frac{4}{3}$

<em>Hence (a), is true</em>

5 0

3 years ago

The sum of a triangle's sides is

Wewaii [24]

Step-by-step explanation:

Therefore the third side should be less than 12+15 = 27cm

And also the third side cannot be less than the difference of the two sides

Therefore, the third has to be more than 15-12 = 3cm

Thus, the third side could be the length more than 3cm and less than 27cm.

7 0

3 years ago

PLEASE HELP ME ANSWER THIS<br> What is cos 60?

Anna71 [15]

Answer:

The angle with measure 60° is one of those angles that has a well-known cosine value: cos(60°) its C= 1/2.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Solve the equation sin2x = 3cos2x. The value of x that satisfies the equation if x lies in the second quadrant is °. The value o

faltersainse [42]

Answer:

$126\degree$

and

$126\degree$

respectively.

Step-by-step explanation:

The given trigonometric equation is

$\sin2x=3\cos2x$

We divide both sides by $\cos2x$ to get,

$\frac{\sin2x}{\cos2x}=3$

This implies that,

$\tan2x=3$

We take the inverse tangent of both sides to get,

$2x=\tan^{-1}(3)$

$\Rightarrow 2x=71.565$

$\Rightarrow x=35.7825$

$\Rightarrow x\approx 36\degree$

Since the tangent ratio has a period of $180\degree$ , another solution is

$x=180+36$

$x=216\degree$ to the nearest degree.

In the third quadrant,

$2x=180+71.565$

$\Rightarrow 2x=251.565$

$\Rightarrow x=125.7825$

$\Rightarrow x=126\degree$

The solutions are

$x=36\degree,126\degree,216\degree$

The value of x that satisfies the equation if x lies in the second quadrant is $126\degree$

The value of x that satisfies the equation if x lies in the third quadrant is $216\degree$

5 0

3 years ago